Answer:
Tritium is more stable.
This happens in part because the tritium nucleus has an extra neutron enhancing the nuclear forces.
Explanation:
The binding energy is the energy that holds nucleons together in the nucleus. It depends on the number of nucleons present in the nucleus. The greater the number of nucleons, the greater the binding energy.
Also, the more the number of neutrons in a nucleus, the greater the nuclear forces. Helium-3 has only one neutron while tritium has two neutrons. The extra neutron in tritium enhances the nuclear forces hence tritium has a greater binding energy than Helium-3
Answer:
1000.66m
Explanation:
![l 2 = l1(1 + \alpha \: \times change \:in \: temperature)](https://tex.z-dn.net/?f=l%202%20%3D%20l1%281%20%2B%20%20%5Calpha%20%5C%3A%20%20%20%5Ctimes%20change%20%5C%3Ain%20%5C%3A%20temperature%29)
L1=1000m
Temperature 1=-20
L2=?
Temperature 2=40
Temperature difference=40-(-20)
40+20=60
inserting into the formula
l2=l1(1+α×changeintemperature)
L2=1000(1+11×10^-6 ×60)
L2=1000(1+6.6×10^-4)
L2=1000(1.000.66)
L2=1000.66m
The answer to your question I think it is A but I’m not 100%
Some properties I know are
melting point<span>
, </span>
boiling point<span>
, and index of </span>
refraction<span>.</span>
Answer:
λ = 6 10⁻⁷ m
Explanation:
This problem is a double slit interference spectrum where bright maxima are described by constructive interference.
d sin θ = m λ
Where d is the gap of the slits (d = 0.2 10⁻³ m), m is the maximum interference and λ is the wavelength
We used trigonometry to find the angle
tan θ = y / x
Since the angles in these experiments are very small we use
tan θ = sin θ / cos θ = sin θ
sin θ = y / x
We substitute
d y / x = m λ
λ = d y / m x
In this case the first maximum is m = 1
We substitute
λ = 0.2 10⁻³ 3.6 10⁻³ / (1 1.2)
λ = 6 10⁻⁷ m
The approximation made in this problem is that since the angles are small we approximate the tangent to the sine