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4 years ago

What are two things that turbines have been used for?

Physics

2 answers:

posledela4 years ago

5 0

2 thing it is used for are commonly like wind turbines and water turbines.

sasho [114]4 years ago

5 0

Wind mills and water mills

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The more mass an object has,the less inertia the object has. True or False

dedylja [7]

Answer:

This is true. objects that have a greater mass has greater interia. which also means objects that have a less mass has also less interia.

Explanation:

i hope this helps!!!

7 0

3 years ago

From a branch 35 m high, a 0.75 kg bird dives into a small fish tank containing

Bad White [126]

Answer:

ΔT = 1.22*10^-3 °C

Explanation:

First, you calculate the potential energy of the bird when it is at 35 m high. The potential energy is also the mechanical energy of the bird in this case.

$U=mgh$

m: mass of the bird = 0.75kg

g: gravitational constant = 9.8m/s^2

h: height = 35m

$U=(0.75kg)(9.8m/s^2)(35m)=257.25\ J$

All this energy is given to the water. You use the following formula in order to calculate the change in temperature:

$Q=mc\Delta T$

m: mass of the water = 50kg

c: specific heat of water = 4186 J/kg°C

Q is equal to U (potential energy of the bird) because the bird gives all its energy to water. By doing ΔT the subject of the formula you obtain:

$\Delta T=\frac{Q}{mc}=\frac{257.25J}{(50kg)(4186J/kg°C)}=1.22*10^{-3}\ \°C$

hence, the maximum rise in temperature is 0.00122 °C

7 0

3 years ago

Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas

Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

$I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I = 11.35kgm^2\\$

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

$I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2$

C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,

$I = \frac{1}{2}*l^2$

$I = \frac{1}{2}*(4.7)^2$

$I = 11.045kgm^2$

7 0

3 years ago

Electron (-) has a charge of 1.6 x 10-19 C. Proton (+) has a charge of 1.6 x 10-19 C. In a hydrogen atom the distance between a

gladu [14]

Answer:

c because you can lift a 2 pound dumbell

7 0

4 years ago

A bicycle of mass m requires 50 J of work to move from rest to a final speed v. If the same amount of work is performed during t

insens350 [35]

Answer:

The final speed of the second bicycle is (v·√2)/2

Explanation:

The mass of the given bicycle = m

The amount of work required to move the bicycle from rest to speed v = 50 J

The final speed of the first bicycle = v

The mass of the second bicycle = 2m

Therefore, from conservation of energy, we have;

Work required by the first bicycle = Kinetic energy gained by the bicycle

The kinetic energy = 1/2·m·v²

∴ Energy required by the first bicycle = 50 J = 1/2·m·v²

Given that the same amount of work is performed on the second bicycle, we have;

Work performed on the second bicycle = 50 J = kinetic energy of second bicycle = 1/2·(2·m)·v₂²

Also, given that 50 J = 1/2·m·v², we have;

Work performed on the second bicycle = 50 J = 1/2·m·v²= 1/2·(2·m)·v₂²

1/2·m·v²= 1/2·(2·m)·v₂²

m·v² = 2·m·v₂²

v² = 2·v₂²

v₂ = √(v²/2) = v/√2 = (v·√2)/2

v₂ = (v·√2)/2

The final speed of the second bicycle = v₂ = (v·√2)/2.

3 0

3 years ago