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larisa86 [58]
3 years ago
10

LIst properties common to many organic compounds

Physics
1 answer:
stich3 [128]3 years ago
7 0
Some properties I know are melting point<span>, </span>boiling point<span>, and index of </span>refraction<span>.</span>

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If you jumped out of a plane, you would begin speeding up as you fall downward. Eventually, due to wind resistance, your velocit
MrRa [10]

Answer:

Mg or your weight.

Explanation:

When your velocity is constant, the net force acting on you is 0. That means the upwards force of air resistance must fully balance the downwards force of gravity on you, which is Mg.

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3 years ago
From this diagram which of the following can you conclude
Volgvan

Answer: A

Explanation:

I say opposites attract

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3 years ago
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A pingpong ball has 2 kg m/s of momentum when thrown 8 m/s find the mass of the ball
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Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

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Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s
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1,323 days left

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3 years ago
Consider a block on frictionless ice. Starting from rest, the block travels a distance din
sweet [91]

Answer:

<em>The distance is now 4d</em>

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

The acceleration can be calculated by solving for a:

\displaystyle a=\frac{F}{m}

Once we know the acceleration, we can calculate the distance traveled by the block as follows:

\displaystyle d = vo.t+\frac{at^2}{2}

If the block starts from rest, vo=0:

\displaystyle d = \frac{at^2}{2}

Substituting the value of the acceleration:

\displaystyle d = \frac{\frac{F}{m}t^2}{2}

Simplifying:

\displaystyle d = \frac{Ft^2}{2m}

When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:

\displaystyle a'=\frac{4F}{m}

And the distance is now:

\displaystyle d' = \frac{4Ft^2}{2m}

Dividing d'/d:

\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}

Simplifying:

\displaystyle \frac{d' }{d}=4

Thus:

d' = 4d

The distance is now 4d

3 0
2 years ago
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