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docker41 [41]
4 years ago
11

The net force on a car is zero in both the horizontal and vertical directions which two situations could be true about the motio

n of the car
Physics
2 answers:
Alina [70]4 years ago
8 0

Two possible situations:

- The car is at rest. In this case, there are only 2 forces acting on the car, both in the vertical direction: the weigth of the car (downward) and the normal reaction of the asphalt on the car (upward). The two forces are equal in magnitude but in opposite directions, so the net force is zero.

- The car is traveling at constant velocity. In this case, there are 4 forces: in the vertical direction, as before, we have the weigth of the car (downward) and the normal reaction of the asphalt on the car (upward). The two forces are equal in magnitude but in opposite directions, so the net force in the vertical direction is zero. However, this time the car is also moving, so there are forces acting along the horizontal direction: the driving force, which pushes the car forward, and the frictional force, which goes in the opposite direction. Since the car is moving at constant velocity, its acceleration is zero, so the net force must be zero: therefore, the magnitude of these two forces is equal.

galben [10]4 years ago
8 0
Since both the net force of the horizontal and vertical directions on the car is zero, we can imply that it is in equilibrium in two cases: either it is at rest, or it is moving on a constant velocity. I hope my answer has come to your help. God bless and have a nice day ahead!
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Which of the following best describes entropy
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Answer:

Exothermic reactions increase the entropy of the surroundings. Simply put, entropy measures the dispersal of energy. Since ΔH is negative in an exothermic reaction, this must mean that ΔS will take on a positive value, indicating an increase in entropy.

3 0
3 years ago
How do mountain glaciers and continental glaciers differ in terms of dimensions, thickness and patterns of movement?
tester [92]
Question:
How do mountain glaciers and continental glaciers differ in terms of dimensions, thickness and patterns of movement?

Answer:
<span>
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Hope this helped!

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8 0
4 years ago
The question states: two large, parallel conducting plates are 12cm
AnnZ [28]

Answer:

1. 24375 N/C

2. 2925 V

Explanation:

d = 12 cm = 0.12 m

F = 3.9 x 10^-15 N

q = 1.6 x 10^-19 C

1. The relation between the electric field and the charge is given by

F = q E

So, E=\frac{F}{q}

E=\frac{3.9 \times 10^{-15}}{1.6 \times 10^{-19}}

E = 24375 N/C

2. The potential difference and the electric field is related by the given relation.

V = E x d

where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.

By substituting the values, we get

V = 24375 x 0.12 = 2925 Volt

6 0
3 years ago
Which processes cause rocks to be exposed<br> at Earth's surface? SC.7..6.2
seropon [69]

Answer:

weathering

Explanation:

5 0
3 years ago
An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the
alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

X=V_{o}*t + \frac{a*t^{2}}{2}   Replacing the known values:

1500=6t+0.9*t^{2}    Solving for t we get 2 possible answers:

t1 = -44.3s   and t2 = 67.7s    Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0
3 years ago
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