1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesna [10]
3 years ago
13

Other than the depth and the atmospheric pressure, state one quantity that affects the

Physics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

density

Explanation:

pressure within a liquid a liquid only depends on the density of the liquid,the acceleration due to gravity, and the depth within the liquid

You might be interested in
Four electrons and one proton are at rest, all at an approximate infiitne distance away from each other. This original arrangmen
murzikaleks [220]

Answer:

a)  W = 1.63 10⁻²⁸ J,  b)  W = 1.407 10⁻²⁷ J, c) W = 1.68 10⁻²⁸ J,

d)  W = - 4.93 10⁻²⁸ J

Explanation:

a) In this problem we have an electron at the origin, work is requested to carry another electron from infinity to the point x₂ = 0, y₂ = 2.00m

If we use the law of conservation of energy, work is the change in energy of the system

          W = ΔU = U_∞ -U

the potential energy for point charges is

           U =k \sum \frac{q_i q_j}{r_{ij} }

in this case we only have two particles

           U = k \frac{q_1q_2}{r_{12} }

the distance is

           r₁₂ = \sqrt{(x_2-x_1)^2 + ( y_2-y_1)^2      }

           r₁₂ =\sqrt{ 0 + ( 2-0)^2}Ra 0 + (2-0)

           r₁₂ = √2= 1.4142 m

     

we substitute

           W = k \sum \frac{q_i q_j}{r_{ij} }

         

let's calculate

            W = \frac{ 9 \ 10^9 (1.6 \ 10^{-19})^2  }{1.4142} 9 109 1.6 10-19 1.6 10-19 / 1.4142

            W = 1.63 10⁻²⁸ J

b) the two electrons are fixed, what is the work to bring another electron to x₃ = 3.00 m y₃ = 0

             

in this case we have two fixed electrons

            U = k ( \frac{q_1q_3}{r_{13} }  + \frac{q_2q_3}{r_{23} } )

in this case all charges are electrons

             q₁ = q₂ = q₃ = q

             W = U = k q² ( \frac{1}{r_{13} } + \frac{1}{r_{23} } )

the distances are

            r₁₃ = \sqrt{(3-0)^2 + 0}RA (3.00 -0) 2 + 0

            r₁₃ = 3

            r₂₃ = \sqrt{ 3^2 + 2^2}Ra (3 0) 2 + (2 0) 2

            r₂₃ = √13

            r₂₃ = 3.606 m

let's look for the job

            W = U

let's calculate

            W ={9 \ 10^3 ( 1.6 10^{-19})^2 }({\frac{1}{3} + \frac{1}{3.606} } )

            W = 1.407 10⁻²⁷ J

c) the three electrons are fixed, we bring the four electron to x₄ = 3.00m,

y₄ = 4.00 m

             W = U = k ( \frac{q_1q_4}{r_{14 }} + \frac{q_2q_4}{r_{24} } + \frac{q_3q_4}{r_{34} }   )

all charges are equal q₁ = q₂ = q₃ = q₄ = q

             W = k q² (\frac{1}{r_{14} } + \frac{1}{r_{24} } + \frac{1}{r_{34} }  )

             

let's look for the distances

             r₁₄ = \sqrt{3^2 +4^2}

             r₁₄ = 5 m

             r₂₄ = \sqrt{3^2 + ( 4-2)^2}

             r₂₄ = √13 = 3.606 m

             r₃₄ = \sqrt{(3-3)^2 + (4-0)^2}

            r₃₄ = 4 m

we calculate

           W = 9 10⁹ (1.6 10⁻¹⁹)²  ( \frac{1}{5} + \frac{1}{3.606} + \frac{1}{4} )

           W = 1.68 10⁻²⁸ J

d) we take the proton to the location x5 = 1m y5 = 1m

            W = U = k ( \frac{q_1q_5}{r_{15} } + \frac{q_2q_5}{r_{25} } + \frac{q_3q_5}{r_{35} } + \frac{q_4q_5}{r_{45} } )

in this case the charges have the same values ​​but charge 5 is positive and the others negative, so the products of the charges give a negative value

            W = - k q² ( \frac{1}{r_{15} } + \frac{1}{r_{25} } + \frac{1}{r_{35} } + \frac{1}{r_{45} }  )

we look for distances

            r₁₅ = \sqrt{ 1^2 +1^2}Ra (1-0) 2 + (1-0) 2

            r₁₅ = √ 2 = 1.4142 m

            r₂₅ = \sqrt{ (2-1)^2 +1^2}

            r₂₅ = √2 = 1.4142 m

            r₃₅ = \sqrt{ ( 3-1)^2 +1^2}

            r₃₅ = √5 = 2.236 m

            r₄₅ = \sqrt{ (3-1)^2 + (4-1)^2}

            r₄₅ = √13 = 3.606 m

we calculate

           W = - 9 10⁹ (1.6 10⁻¹⁹)² ( \frac{1}{1.4142} +\frac{1}{1.4142} + \frac{1}{2.236} + \frac{1}{3.606} )

            W = - 4.93 10⁻²⁸ J

3 0
3 years ago
Which of the following is an example of electrical energy being converted to chemical energy?
tekilochka [14]

Answer : The correct option is, (B)

Explanation :

Electrical energy : It is defined as the movement of the electrons thought the wire.

Chemical energy : It is a type of energy which is stored in the bonds of a chemical compounds. During the chemical reaction, chemical energy is released in the form of heat.

Sound energy : It is a type of energy which is produced when an object vibrate.

Mechanical energy : It is a type of energy that can be used to do work.

The option A is incorrect because in this process, electrical energy being converted to the sound energy.

The option B is correct because in this process, electrical energy being converted to chemical energy. An oxidation-reduction reaction occurs in the storage battery.

The option C is incorrect because in this process, mechanical energy being converted to mechanical energy.

Hence, the option (B) A storage battery is charged using an electric current is an example of electrical energy being converted to chemical energy.

7 0
4 years ago
Read 2 more answers
The force of gravity depends on the mass of objects and the distance between them. TRUE OR FALSE?
Svet_ta [14]
It is TRUE, Force is proportional to the product of the masses and inversely proportional to the square of the distance between them.
4 0
4 years ago
Two physics students shoot a water-bottle rocket from a 1 m tall stand. They calculate that rocket will travel with the given fo
Kitty [74]

Answer:

2 secs; 65 feet

Explanation:

The function guiding the water bottle is given as:

f(x) = -16t² + 64t + 1

The bottle will reach maximum height when velocity, df/dt (velocity is the first derivative of distance) = 0.

Therefore:

df/dt = 0 = -32t + 64

=> 32t = 64

t = 64/32 = 2 seconds

This is the time it will take to reach the maximum height.

To find this height, we insert t = 2 into the function f(x):

f = -16(2)² + 64(2) + 1

f = -(16 * 4) + 128 + 1

f = -64 + 128 + 1

f = 65 ft

Its maximum height is 65 ft.

7 0
3 years ago
Read 2 more answers
Usain Bolt (m = 86.2 kg)
guapka [62]

Answer: 138 N

Explanation:

6 0
3 years ago
Other questions:
  • A roller coaster is at the top of a hill and rolls to the top of a lower hill if mechanical energy is constant then on the top o
    15·1 answer
  • Which of these scenarios in a ripple tank would result in destructive interference?
    9·2 answers
  • Show that the equation below is dimensionally correct. y=vo t + 1/2 a t2 . ( where a is acceleration , v is the velocity and y i
    6·1 answer
  • A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh
    15·1 answer
  • A certain strain of bacteria doubles in number each 20 days. Two of these bacteria are placed on
    5·1 answer
  • What kind of motion indicates a system where the net force equals zero?
    6·2 answers
  • The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge
    14·1 answer
  • Help!!!!
    12·2 answers
  • Which type of force is a noncontact force?​
    14·2 answers
  • A nurse asks a doctor about medication for a
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!