Answer:
50,000 V/m
Explanation:
The electric field between two charged metal plates is uniform.
The relationship between potential difference and electric field strength for a uniform field is given by the equation

where
is the potential difference
E is the magnitude of the electric field
d is the distance between the plates
In this problem, we have:
is the potential difference between the plates
d = 15 mm = 0.015 m is the distance between the plates
Therefore, rearranging the equation we find the strength of the electric field:

Given:
mass = 6 kg
velocity = 4 m/s
To find:
Kinetic energy of the cart = ?
Formula used:
Kinetic energy = 
Where m = mass of the cart
v = velocity with which the cart is moving
Solution:
Kinetic energy of the moving cart is given by,
Kinetic energy = 
Where m = mass of the cart
v = velocity with which the cart is moving
Kinetic energy =
Kinetic energy = 48 Joule
Thus, the kinetic energy of the moving cart is 48 Joule.
Answer:
the bending moment will be W from either sides
Explanation:
bending moment= force (load) * perpendicular distance, if I understand the question the distance will be 1/2 of the length
=> f x 1/2(l) =W*1/2(2) =W
Answer:
The speed is 33.5 m/s.
Explanation:
Given that,
Mass = 0.064 kg
Wavelength 
We need to calculate the speed
Using formula of he de Broglie wavelength


Where, h = Planck constant
m = mass
= wavelength
Put the value into the formula


Hence, The speed is 33.5 m/s.
Answer:
Kinetic energy of the system = 2547.41 Joules.
Explanation:
Given:
Disk:
Mass of the disk (m) =
kg
Radius of the disk (r) =
cm =
m
Cylinder:
Mass of the annular cylinder (M) =
kg
Inner radius of the cylinder
=
m
Outer radius of the cylinder
=
m
The angular speed of the system
=
rev/s
Angular speed in in terms of Rad/sec =
rad/sec
Formula to be used:
Rotational Kinetic energy,
= 
So, before that we have to work with the moment of inertia (MOI) of the system.
⇒ MOI of the system = MOI of the disk + MOI of the cylinder
⇒ MOI (system) = 
⇒ MOI (system) = 
⇒ MOI (system) =
kg.m^2
Now
The rotational Kinetic energy.
⇒ 
Plugging the values.
⇒ 
⇒
Joules
Then
The kinetic energy of the rotational system is 2547.41 J.