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Oksanka [162]
3 years ago
5

A nurse asks a doctor about medication for a

Physics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

medication error thats easy

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Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between
Romashka [77]

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

\Delta V=Ed

where

\Delta V is the potential difference

E is the magnitude of the electric field

d is the  distance between the plates

In this problem, we have:

\Delta V=750 V is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m

6 0
4 years ago
How much kinetic energy does a 6kg cart have when moving at 4 m/s?
Arturiano [62]

Given:

mass = 6 kg

velocity = 4 m/s

To find:

Kinetic energy of the cart = ?

Formula used:

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Solution:

Kinetic energy of the moving cart is given by,

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Kinetic energy =\frac{1}{2} \times 6 \times \ 4 \times 4

Kinetic energy = 48 Joule

Thus, the kinetic energy of the moving cart is 48 Joule.

3 0
4 years ago
A uniform beam of arbitrary, unsymmetrical cross-section and length 2???? is built-in at one end and simply supported in the ver
leonid [27]

Answer:

 the bending moment will be W from either sides

Explanation:

bending moment= force (load) * perpendicular distance, if I understand the question the distance will be 1/2 of the length

=> f x 1/2(l) =W*1/2(2) =W

5 0
3 years ago
The de Broglie wavelength of a 0.064-kg golf ball is 3.09 x 10^−34m. What is its speed? (h = 6.63 x 10^−34 J⋅s)
tatyana61 [14]

Answer:

The speed is 33.5 m/s.

Explanation:

Given that,

Mass = 0.064 kg

Wavelength \lambda= 3.09\times10^{-34}\ m

We need to calculate the speed

Using formula of he de Broglie wavelength

\lambda=\dfrac{h}{mv}

v=\dfrac{h}{m\lambda}

Where, h = Planck constant

m = mass

\lambda = wavelength

Put the value into the formula

v = \dfrac{6.63\times10^{-34}}{0.064\times 3.09\times10^{-34}}

v=33.5\ m/s

Hence, The speed is 33.5 m/s.

3 0
3 years ago
A system consists of a disk of mass 2.33 kg and radius 50 cm upon which is mounted an annular cylinder of mass 2.20 kg with inne
Gekata [30.6K]

Answer:

Kinetic energy of the system = 2547.41 Joules.

Explanation:

Given:

Disk:

Mass of the disk (m) = 2.33 kg

Radius of the disk (r) = 50 cm = \frac{50}{100} =0.5 m

Cylinder:

Mass of the annular cylinder (M) = 2.20 kg

Inner radius of the cylinder (R_i) = 0.2 m

Outer radius of the cylinder (R_o) = 0.3 m

The angular speed of the system (\omega) = 15.1 rev/s

Angular speed in in terms of Rad/sec = 15.1\times 2\pi =94.876 rad/sec

Formula to be used:

Rotational Kinetic energy, (KE)_r = \frac{I\times \omega^2}{2}

So, before that we have to work with the moment of inertia (MOI) of the system.

⇒ MOI of the system = MOI of the disk + MOI of the cylinder

⇒ MOI (system) = \frac{mr^2}{2} +\frac{M(R_i+R_o)^2}{2}

⇒ MOI (system) = \frac{2.33\times (0.5)^2}{2} + \frac{2.20\times (0.2+0.3)^2}{2}

⇒ MOI (system) = 0.566 kg.m^2

Now

The rotational Kinetic energy.

⇒ (KE)_r =\frac{I\omega^2}{2}

Plugging the values.

⇒  (KE)_r=\frac{0.566\times (94.876)^2}{2}

⇒ (KE)_r=2547.41 Joules

Then

The kinetic energy of the rotational system is 2547.41 J.

5 0
3 years ago
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