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Sav [38]
4 years ago
11

How do you classify a substance with a pH of 3?

Chemistry
1 answer:
otez555 [7]4 years ago
7 0

If a pH is lower than 7 it indicates the solution is an acid.

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Which statement is true about HCI?
katen-ka-za [31]

Answer:

d- it is an acid because it increases the concentration of hydronium ions

Explanation:

HCl; hydrochloric acid is an acid because it increases the concentration of hydronium ions when in solutions.

An acid is a substance that interacts with water to produce excess hydroxonium ions H₃O⁺ in an aqueous solution.

For example:

               HCl + H₂O → H₃O⁺ + Cl⁻

HCl is classified as a strong acid due to its complete ionization when in solutions.

3 0
3 years ago
Which particle has a negative charge?
sweet [91]

Answer: A

Explanation: Beta particles have a charge of -1

6 0
3 years ago
Read 2 more answers
What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3
Nataly_w [17]

We need the  IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

3 0
3 years ago
Read 2 more answers
What mass of salt (nacl) should you add to 1.48 l of water in an ice cream maker to make a solution that freezes at -13.4 ∘c ? a
blagie [28]
Answer is: mass of salt is 311,15 g.
V(H₂O) = 1,48 l · 1000 ml/l = 1480 ml.
m(H₂O) = 1480 g = 1,48 kg.
d(solution) = 1,00 g/ml.
ΔT(solution) = 13,4°C = 13,4 K.
Kf = 1,86 K·kg/mol; cryoscopic constant of water
i(NaCl) = 2; Van 't Hoff factor.
ΔT(solution) = Kf · b · i.
b(NaCl) = 13,4 K ÷ (1,86 K·kg/mol · 2).
b(NaCl) = 3,6 mol/kg.
n(NaCl) = 3,6 mol · 1,48 kg= 5,328 mol.
m(NaCl) = 5,328 mol · 58,4 g/mol = 311,15 g.

5 0
3 years ago
Read 2 more answers
A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

3 0
3 years ago
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