How do you classify a substance with a pH of 3?

Which of the compounds, C3H8, mgcl2, OCl2 are expected to exist as molecular compounds?

Rina8888 [55]

Answer:

C3H8 and OCI2

Explanation:

They are molecular compounds. MgCL2 is an iconic compound. Molecular compounds are covalent compounds in which the elements share electrons via covalent bonds.

8 0

3 years ago

Using complete subshell notation (not abbreviations, 1s 22s 22p 6 , and so forth), predict the electron configuration of each of

dybincka [34]

Answer: The electronic configuration of the elements are written below.

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

For the given options:

Option a: Carbon (C)

Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.

The electronic configuration of carbon is $1s^22s^22p^2$

Option b: Phosphorus (P)

Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.

The electronic configuration of phosphorus is $1s^22s^22p^63s^23p^3$

Option c: Vanadium (V)

Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.

The electronic configuration of vanadium is $1s^22s^22p^63s^23p^64s^23d^3$

Option d: Antimony (Sb)

Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.

The electronic configuration of antimony is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^3$

Option e: Samarium (Sm)

Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.

The electronic configuration of samarium is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^6$

Hence, the electronic configuration of the elements are written above.

4 0

3 years ago

How many electrons can the n=4 shell hold? a. 8b.16c.32d.64?

ra1l [238]

The maximum the fourth shell can have is 32.

6 0

3 years ago

Read 2 more answers

0.023 M solution of perchloric acid

kogti [31]

The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)

5 0

3 years ago

A chemist has some 40% acid solution, some 60% acid solution, and a wholebunch of free time. How many liters of each should be u

TiliK225 [7]

Answer:

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

Explanation:

Let volume of the 40% acid solution be x.

Let volume of the 60% acid solution be y.

Volume of solution formed after mixing both solution = 40 L

x + y = 40 L..[1]

Volume of acid 40% solution = 40% of x= 0.4x

Volume of acid 60% solution = 60% of y= 0.6y

Volume of acid formed = 45% of 40 L = $\frac{45}{100}\times 40=18L$

$0.4x+0.6y=18 L$ ..[2]

Solving [1] and [2]

x = 30 L , y = 10 L

30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.

8 0

3 years ago