We will use Ideal gas equation.
PV=nRT
where
P= pressure(in atm)=5.82atm
V=Volume=?
n= moles of gases=0.682
R = gas constant= 0.0821L atm / mol K
T = temperature= 68.2 C= 68.2 + 273.15 = 341.35 K
V= nRT/ P= 0.682 X 0.0821 X 341.35/ 5.82
V= 3.284 L.
Step by step solution:
Its given;
Moles of neon at STP is 15 mol
We are required to calculate the volume;
According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
That is, 1 mole of a gas = 2.4 L
Therefore;
1 mole of Neon gas = 22.4 L
Volume = Moles of the gas × molar gas volume
= 15 mol × 22.4 L/mol
= 336 L
Answer:
there is 2% of hydrogen and 98% of nitrogen (mass percent)
Explanation:
assuming ideal gas behaviour
P*V=n*R*T
n= P*V/(R*T)
where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)
thus
n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles
since the number of moles is related with the mass m through the molecular weight M
n=m/M
thus denoting 1 as hydrogen and 2 as nitrogen
m₁+m₂ = mt (total mass)
m₁/M₁+m₂/M₂ = n
dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁
w₁/M₁+w₂/M₂ = n/mt
w₁/M₁+(1-w₁) /M₂ = n/mt
w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂)
replacing values
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)
and w₂= 1-w₁= 0.98 (98%)
thus there is 2% of hydrogen and 98% of nitrogen
Answer:
composting scraps
recycling is the action or process of converting waste into reusable material.
