Answer:
T = 19.75 N
Explanation:
given,
mass of ball = 0.25 Kg
radius = 0.5 m
frequency = 2 s⁻¹
tension in the string = ?
angular velocity
ω = 2 π f
ω = 2 π x 2
ω = 12.57 rad/s
tension on the string is equal to the centripetal force
T = m ω² r
T = 0.25 x 12.57² x 0.5
T = 19.75 N
Tension in the string is equal to T = 19.75 N
We have to add two vectors.
Vector #1: 0.15 m/s north
Vector #2: 1.50 m/s east
Their sum:
Magnitude: √(0.15² + 1.50²)
Magnitude = √(0.0225+2.25)
Magnitude = √2.2725
Magnitude = <em>1.5075 m/s</em>
Direction = arctan(0.15/1.50) north of east
Direction = <em>5.71° north of east</em>
The absence of external forces will make the pucks move in the form of a uniform circular motion.
<h3>What is a circular motion?</h3>
It should be noted that a circular motion simply means the movement of an object along the circumference of the circle.
In this case, the absence of external forces will make the pucks move in the form of a uniform circular motion.
If the friction is absent, the pucks will continue to move on the same path due to the first law of Newton and the law of conversation of energy. In this case,the results will match the predictions until there's loss in energy.
Learn more about circular motion on:
brainly.com/question/106339
Answer: Because of the longitudinal motion of the air particles, there are regions in the air where the air particles are compressed together and other regions where the air particles are spread apart. These regions are known as compressions and rarefactions respectively
Explanation:
Answer:
M₀ = 5i - 4j - k
Explanation:
Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e
M₀ = r x F
From the question,
r = i + j + k
F = 1i + 0j + 5k
Therefore,
M₀ = (i + j + k) x (1i + 0j + 5k)
M₀ = ![\left[\begin{array}{ccc}i&j&k\\1&1&1\\1&0&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%261%5C%5C1%260%265%5Cend%7Barray%7D%5Cright%5D)
M₀ = i(5 - 0) -j(5 - 1) + k(0 - 1)
M₀ = i(5) - j(4) + k(-1)
M₀ = 5i - 4j - k
Therefore, the moment about the origin O of the force F is
M₀ = 5i - 4j - k
