Answer:
V = 5.83 m/s
Explanation:
Given that,
Mass of a ball of a clay, m = 2 kg
Initial speed of the clay, u = 35 m/s
Mass of a box, m' = 10 kg
Initially, the box was at rest, u' = 0
We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.
So, the velocity of the box after the collision is equal to 5.83 m/s.
Answer:
Explanation:
When the rock is immersed in unknown liquid the forces that act on it are shown as under
1) Tension T by the string
2) Weight W of the rock
3) Force of buoyancy due to displaced liquid B
For equilibrium we have
=
When the rock is suspended in air for equilibrium we have
When the rock is suspended in water for equilibrium we have
+
=
Using the given values of tension and solving α,β,γ simultaneously for we get
Solving for density of liquid we get
Answer:
Hence the answer is E inside .
Explanation:
E inside
so if r1 will be the same then
E proportional to 1/R3
so if R become 2R
E becomes 1/8 of the initial electric field.