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3 years ago

A train travels with a constant speed of 20.0m/s for 7.00s. Determine all

Physics

1 answer:

Bad White [126]3 years ago

8 0

Answer:

acceleration is zero m/s²

Explanation:

It is given that the train travels at constant speed (i.e speed does not change)

If speed does not change, then the train is neither accelerating or decelerating (i.e acceleration is zero)

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Compare the results of applying the acceleration equation in the following 2 cases : (1) an object that goes from 0 to 10 m/s in

erastovalidia [21]

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3 years ago

Considering this analogy (current = rate that heat flows through a window, and voltage = temperature difference across the windo

erastovalidia [21]

Answer:

Explained

Explanation:

Resistance R in a current flow through an object is given by

$R= \frac{\rho L}{A}$

ρ = resistivity of the material

L= length of the object

A= area of cross section

clearly resistance is directly dependent on length of the object.This means greater the length larger will be resistance to current.

thermal resistance R_th is given by

$R_{th} = \frac{L}{KA}$

L= length of the object

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K = Conductivity of the material

thermal resistance is also is directly dependent on length of the object.This means greater the length larger will be resistance to current.

8 0

3 years ago

Read 2 more answers

The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C. What is its vapor pressure at 60.6°C? The molar heat of vaporization

ANEK [815]

Answer:

The vapor pressure at 60.6°C is 330.89 mmHg

Explanation:

Applying Clausius Clapeyron Equation

$ln(\frac{P_2}{P_1}) = \frac{\delta H}{R}[\frac{1}{T_1}- \frac{1}{T_2}]$

Where;

P₂ is the final vapor pressure of benzene = ?

P₁ is the initial vapor pressure of benzene = 40.1 mmHg

T₂ is the final temperature of benzene = 60.6°C = 333.6 K

T₁ is the initial temperature of benzene = 7.6°C = 280.6 K

ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol

R is gas rate = 8.314 J/mol.k

$ln(\frac{P_2}{40.1}) = \frac{31,000}{8.314}[\frac{1}{280.6}- \frac{1}{333.6}]\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.003564 - 0.002998)\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.000566)\\\\ln(\frac{P_2}{40.1}) = 2.1104\\\\\frac{P_2}{40.1} = e^{2.1104}\\\\\frac{P_2}{40.1} = 8.2515\\\\P_2 = (40.1*8.2515)mmHg = 330.89 mmHg$

Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

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3 years ago

Read 2 more answers

Which word best describes this?<br> Particle<br> O Atom<br> O Molecule<br> O Substance

skelet666 [1.2K]

That’s an atom

I hope that helped

3 0

2 years ago

The initial velocity of a micro van is 15 m/s. It gains a velocity of 40 ms in 10 seconds. Calculate the average velocity and ac

PSYCHO15rus [73]

Answer:

${ \bf{average \: velocity = \frac{15 + 40}{2}}} \\ = 27.5 \: {ms}^{ - 1} \\ { \bf{acceleration = \frac{v - u}{t} }} \\ = \frac{40 - 15}{10} \\ = 2.5 \: {ms}^{ - 2} \\ \\ { \tt{second \: qn : }} \\ { \bf{final \: velocity =u + at }} \\ v = 0 + (5 \times 10) \\ = 50 \: {ms}^{ - 1}$

5 0

2 years ago