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2 years ago

A red blood cell has a diameter of approximately 8 micrometers, or 0.008 um.

Physics

2 answers:

Lina20 [59]2 years ago

8 0

The correct answer is OD.1,000:1

Murrr4er [49]2 years ago

7 0

<h2><em><u>The actual size would be 1,000:1</u></em></h2><h2><em><u /></em></h2>

<em>thank youuuuu</em>

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What is the acceleration of a 59 kg object pushed with a force of 500 Newton's ?

Igoryamba

Answer:

a=500/50=10 m/s^2

Explanation:

f=m•a a=f/m

a=500/50= 10 m/s^2

4 0

2 years ago

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve

Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

$v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2$

$v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96$

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0

2 years ago

Velocity question...is it A B Cor D

Ket [755]

In a constant acceleration of 3m per second, after 10 seconds,

3 x 10 = 30

B. 30m/s is your answer

hope this helps :D

6 0

2 years ago

Read 2 more answers

when an object moves with constant velocity, does its average velocity during any time interval differ from its instataneous vel

BigorU [14]

For a constant-velocity object, the average and instantaneous are the same. So the answer is no. It's like taking a running average of a string of numbers that are all the same number. The average is always the sum of the numbers divided by how many have accumulated, which will always equate to the repeated number.

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3 years ago

A balloon filled with helium gas at 1.00 atm occupies 15.6 L. Will the volume of the balloon increase or decrease in the upper a

Mariana [72]

Answer:

The volume of the balloon increases in the upper atmosphere.

Explanation:

p1= 1 atm

p2= 0.15 atm

V1= 15.6 L

V2= ?

p1*V1= p2 * V2

V2= (p1/p2)*V1

V2= 104 L

6 0

3 years ago