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Oduvanchick [21]
3 years ago
8

A red blood cell has a diameter of approximately 8 micrometers, or 0.008 um.

Physics
2 answers:
Lina20 [59]3 years ago
8 0
The correct answer is OD.1,000:1
Murrr4er [49]3 years ago
7 0
<h2><em><u>The actual size would be 1,000:1</u></em></h2><h2><em><u /></em></h2>

<em>thank youuuuu</em>

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:<span>  </span><span>Under the assumption that a cell is made up of two concentric spheres you find the surface are of the inside sphere which will be your A. 

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A car starts from rest and after 7.0 seconds it is moving at 42 m/s. What is the car's average acceleration?
andriy [413]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>Q</u><u>UESTION)</u></h3>

<em>✔ We have : a = v/Δt </em>

  • a = 426/7
  • a = 6 m/s²

The car's acceleration is therefore 6 m/s².

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2 years ago
Match each type ol energy with its description
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It is B I sloved it
6 0
3 years ago
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A long solenoid consists of 1700 turns and has a length of 0.75 m.The current in the wire is 0.48 A. What is the magnitude of th
Travka [436]

Answer:

1.37 ×10^-3 T

Explanation:

From;

B= μnI

μ = 4π x 10-7 N/A2

n= number of turns /length of wire = 1700/0.75 = 2266.67

I= 0.48 A

Hence;

B= 4π x 10^-7 × 2266.67 ×0.48

B= 1.37 ×10^-3 T

4 0
3 years ago
A 100-lb child stands on a scale while riding in an elevator. What does the scale read while the elevator slows to stop at the l
Lelechka [254]

Answer: A 100-lb child stands on a scale while riding in an elevator. Then, the scale reading approaches to 100lb, while the elevator slows to stop at the lowest floor

Explanation: To find the correct answer, we need to know more about the apparent weight of a body in a lift.

<h3>What is the apparent weight of a body in a lift?</h3>
  • Consider a body of mass m kept on a weighing machine in a lift.
  • The readings on the machine is the force exerted by the body on the machine(action), which is equal to the force exerted by the machine on the body(reaction).
  • The reaction we get as the weight recorded by the machine, and it is called the apparent weight.
<h3>How to solve the question?</h3>
  • Here we have given with the actual weight of the body as 100lbs.
  • This 100lb child is standing on the scale or the weighing machine, when it is riding .
  • During this condition, the acceleration of the lift is towards downward, and thus, a force of ma .
  • There is also<em> mg </em>downwards and a normal reaction in the upward direction.
  • when we equate both the upward force and downward force, we get,

                             ma=mg-N\\N=mg-ma    i.e. during riding the scale reads a weight less than that of actual weight.

  • When the lift goes slow and stops the lowest floor, then the acceleration will be approaches to zero.

Thus, from the above explanation, it is clear that ,when the elevator moves to the lowest floor slowly and stops, then the apparent weight will become the actual weight.

Learn more about the apparent weight of the body in a lift here:

brainly.com/question/28045397

#SPJ4

7 0
1 year ago
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