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just olya [345]
3 years ago
7

The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?

Physics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

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You hear a fire truck with a certain intensity, and you are about 1 mile away. Another person hears the same fire truck with an
marin [14]

The intensity of sound is just like the force of gravity, the force between electric charges, and the intensity of light . . . they all DEcrease at the same rate that the SQUARE of the distance INcreases.

So if two people are watching or listening to the same source, and one intensity is 1/10 as intense as the other intensity, then the farther person must be  √10  times as far from the source as the nearer person is.

√10 = 3.1622 ...

So the second guy is about <em>3.16 miles</em> from the fire truck.  

4 0
3 years ago
The electric potential difference between the ground and a cloud in a particular thunderstorm is 2.5 × 109 V. What is the magnit
muminat

Answer:

U = - 4 x 10^{-10}

Explanation:

ΔV = potential difference = 2.5 * 10^9 Volts

q = charge on electron = -1.6 * 10^{-19} C

electric potential energy is given as

U = q ΔV = ( -1.6 * 10^{-19}  ) ( 2.5 * 10^9  )

               = - 4 x 10^{-10}

6 0
3 years ago
A 780g, 50-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short but
Semmy [17]

Answer:

9.6 rad/s

Explanation:

L = length of the metal rod = 50 cm = 0.50 m

M = Mass of the long metal rod = 780 g = 0.780 kg

Moment of inertia of the rod about one end is given as

I = \frac{ML^{2}}{3} = \frac{(0.780)(0.50)^{2}}{3} = 0.065 kgm^{2}

F = force applied by the hammer blow = 1000 N

Torque produced due to the hammer blow is given as

\tau = \frac{FL}{2}

\tau = \frac{(1000)(0.50)}{2}

\tau = 250 Nm

t = time of blow = 2.5 ms = 0.0025 s

w = Angular velocity after the blow

Using Impulse-change in angular momentum, we have

I w = \tau t\\(0.065) w = (250) (0.0025)\\w = 9.6 rads^{-1}

5 0
3 years ago
You are rolling on a skateboard with a constant velocity of 12 m/s. As you are moving you toss a baseball straight up into the a
Aliun [14]
Ick! Word problems! They suck. Okay so first of all you want to narrow it dow the equation.


Step 1. What are the numbers? (In this case 12 m/s and 25 m/s)

Step 2. Are you multiplying, dividing? (In this case your dividing)

Step 3. Divide.

I hope that helps.
5 0
3 years ago
The joule is an example of units of work. Which of the following is not a valid unit of work? ft-lb (kg-m2)/s2 inch-ton lb/s2
Dahasolnce [82]

The "<em>lb/s² </em>" is not a valid unit of work.

Each of the others is (a unit of force) x (a unit of distance) which is pretty much the definition of work.

5 0
4 years ago
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