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attashe74 [19]
3 years ago
10

Latasha and we could go on a road trip first they drive 80 miles east to visit a waterfall then they drive 50 miles north to a M

exican restaurant after their meal the friends drive like 40 miles west to visit a cave finally be drive 95 miles south to see a music festival Latasha and Mika are now what distance from the starting point
Mathematics
2 answers:
belka [17]3 years ago
5 0
This is the concept of arithmetic, the total distance that Latasha will be from the airport will be:
distance= sum of distances traveled.
hence we shall have:
distance=80+50+40+95
=265 miles
This implies that Latasha is 265 miles off the starting point.
Mars2501 [29]3 years ago
4 0

Answer: 60.21 miles

 

SOLUTION

 

The trip is as follows:

80 miles East

50 miles North

40 miles West

95 miles South

 

Since, they drove 80 miles East and 40 miles West

Total horizontal displacement = 80 – 40 (Since east and west are in opposite directions)

Total horizontal displacement = 40 miles (East)

 

Since, they drove 50 miles North and 95 miles South

Total vertical displacement = 95 – 50 (Since north and south are in opposite directions)

Total vertical displacement = 45 miles (South)

 

This forms a right angled triangle

40 miles horizontal displacement

45 miles vertical displacement

Current distance from the starting point, d = Hypotenuse of the triangle

 

 

d² = 40² + 45²

d² = 1600 + 2025

d² = 3625

√d² = √3625

d = 60.21 miles

 

Therefore, Latasha and Mike are 60.21 miles from the starting point.

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3 0
3 years ago
Please can someone help me on this
Ivan
X=-6
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