You cross multiple. Remember 5 = 5/1
So x/2 = 5/1
Cross multiple x is linked with 1 and 2 is lined with 5.
So x(1) = 5(2)
X = 10
<span><span><span><span>=−<span><span>2x</span>y</span></span>+<span>3x</span></span>+<span>−<span><span>2x</span>y</span></span></span>+<span>3x
</span></span><span>=<span><span>(<span><span>−<span><span>2x</span>y</span></span>+<span>−<span><span>2x</span>y</span></span></span>)</span>+<span>(<span><span>3x</span>+<span>3x)
=-4xy+6x
</span></span></span></span></span>
And the answer is A. =-4xy+6x
7p - 4 + 12p = -3(5 + p)
7p - 4 + 12p = -15 - 3p
+ 4 + 4
7p + 12p = -11 - 3p
+ 3p + 3p
22p = -11
p = -1/2 Answer
Answer:
The data in statistics is generally supposed to deviate or vary from the mean. Standard deviations of 1, 2, and 3 are commonly used to calculate variability according to the empirical norm. In a normal distribution, we estimate 68 percent, 95 percent, and 98 percent of the data to be within 1, 2, and 3 standard deviations of the mean, respectively. This implies that the given percentage of data will lie within an interval of less than or greater than the standard deviation. If the values within a given standard deviation from the mean are standardized, the z value will always be equal to or less than the given standard deviation.
We should look at a program that aims to help people get out of poverty by using the standard deviation principle. The aim of the program is to provide free seeds to poor people who have been suffering from low yields due to the use of local seeds. If we use the definition of one standard deviation of the mean, or 2 and 3, we will favor the majority of people, but we will leave the poorest people in society behind.
1.924 and 5.77
step 1: find the mean by adding up all the numbers and divide the sum by the number of numbers.
step 2: find the difference between each number and the mean, square the difference
step 3: add up all the results of step 2, divide the sum by (n-1), n is the number of numbers.
step 4: square root the result of step 3.
it is a long process.