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Andreas93 [3]
3 years ago
10

Analizando una biomolécula X, un científico comprueba que está formada por Carbono, Hidrógeno, Oxígeno y Nitrógeno, además de li

berar agua cuando se une con otras moléculas similares al formar polímeros. Considerando estos antecedentes, se puede inferir que la biomolécula X corresponde a: A Esteroides B ácido graso C nucleótido D aminoácido E monosacárido
Chemistry
1 answer:
Cloud [144]3 years ago
6 0

Analyzing a biomolecule X, a scientist verifies that it is made up of Carbon, Hydrogen, Oxygen and Nitrogen, in addition to releasing water when it joins with other similar molecules to form polymers. Considering these antecedents, it can be inferred that biomolecule X corresponds to: A Steroids B fatty acid C nucleotide D amino acid E monosaccharide (for people who dont speak spanish)

ok you answer is probably A

if wrong C maybe

~hope~

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3 examples of density synonyms
DENIUS [597]

frequency.

quantity.

thickness.

body.

closeness.

concretion.

heaviness.

solidity.

3 0
3 years ago
A particular reaction has an enthalpy and entropy of reaction of ∆H = +33 kJ/mol and ∆S = +0.15 kJ/mol⋅K. At the three indicated
Thepotemich [5.8K]

Answer:

Explanation:  check my paage

4 0
2 years ago
The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
astraxan [27]

The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

[H+] = a = 2.210 × 10⁻⁵ M

The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

= 2.210 × 10⁻⁵ M ÷ 0.015 × 100

= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

#SPJ4

Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?

6 0
1 year ago
2KCIO3 -2KCL + 302
Firlakuza [10]

Answer:

a. 6 moles of O₂

b. 4.06×10²⁴ molecules of O₂

c. 3.04 g of KCl

Explanation:

Reaction of decomposition is:

2KClO₃  →  2KCl  +  3O₂

a. See stoichiometry value

2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3

If 2 moles of KClO₃ can decompose to 3 moles of O₂

Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂

b. In this case, the stoichiometry is the same.

Per 2 moles of KClO₃, I produce 2 moles of KCl

Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃

We apply, the last relation:

(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.

How many molecules are in 6.75 moles?

6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂

c. First of all, we convert the mass to moles:

5g . 1mol /122.55g = 0.0408 moles of salt

As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl

We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g

5 0
2 years ago
Need Help!!! What else should I write?
alexira [117]
You should write to make it a different way like with eye contact solution, laundry detergent, etc. You could also write to see if lotion would have an affect on the expandable-ness
4 0
3 years ago
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