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enot [183]
2 years ago
10

What is the joining of atoms to form new substances called?

Chemistry
1 answer:
kirill115 [55]2 years ago
3 0
Chemical bonds is the answer
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The reaction below was carried out in an acidic solution. upper i minus, plus upper i upper o minus subscript 3 right arrow uppe
maria [59]

The reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

<h3>What is a redox reaction?</h3>

The term redox reaction refers to the reactionnin which electrons are transferred hence one specie is oxidized while the other specie is reduced.

Looking at the reation as shown, we can see that the reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

Learn more about redox reaction: brainly.com/question/13293425

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6 0
2 years ago
Find the mass of 0.456 mol of Ca(OH)2 <br> Please if you can show the work.
m_a_m_a [10]

Answer:

Ca(OH)2 molecular weight. Molar mass of Ca(OH)2 = 74.09268 g/mol. This compound is also known as Calcium Hydroxide. Convert grams Ca(OH)2 to moles or moles Ca(OH)2 to grams. Molecular weight calculation: 40.078 + (15.9994 + 1.00794)*2 ››

3 0
2 years ago
Read 2 more answers
If an element gives away an electron, will it form a positive ion or a negative<br> ion?
Elan Coil [88]

Answer:

posotive

Explanation:

electrons give off negative pulse so take one away

8 0
3 years ago
All parts of the rock cycle are connected, whether directly or indirectly. Which statement
Ad libitum [116K]

Answer:

2. Igneous rocks can weather, creating sediments that form sedimentary rocks

Explanation:

Sedimentary rocks are formed from Igneous rocks when rocks are broken down by weathering.

5 0
2 years ago
consider the balanced chemical equation below. when the chemical reaction was carried out calculated theoretical was yield for s
8_murik_8 [283]

Answer:

Explanation:

% yield = (actual yield / theoretical yield) X 100

For this question,

% yield = (150g/ 162 g) X 100 = 92.6%

7 0
3 years ago
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