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strojnjashka [21]
3 years ago
13

Measurements show that the enthalpy of a mixture of gaseous reactants decreases by during a certain chemical reaction, which is

carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic?
Physics
1 answer:
snow_tiger [21]3 years ago
5 0

The given question is incomplete. The complete question is as follows.

Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 338 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 187 kJ of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic ?

Explanation:

The given data is as follows.

    Change in enthalpy (\Delta H) = -338 kJ (as it is a decrease)

    Work done = 187 kJ,

    Change in energy (\Delta E) = ?

Now, according to the first law of thermodynamics the formula is as follows.

          \Delta H = \Delta E + P \Delta V

Hence, putting the given values into the above formula as follows.

        \Delta H = \Delta E + P \Delta V

Also, we know that W = P \Delta V

so,           \Delta H = \Delta E + W      

              -338 kJ = \Delta E + 187

              \Delta E = -151 kJ

Thus, we can conclude that the change in energy of the gas mixture during the reaction is -151 kJ.

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A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car
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Answer:

20 metric tons

Explanation:

Using the Principle of Conservation of Linear Momentum which states that the total momentum of a system is constant in any direction in which no external force acts.

momentum before collision= momentum after collision

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m1u1 + m2u2 = m1v1+m2v2 =0

where:

m1= mass of rolling freight car = 10 metric tons = 10Mg

1 ton = 1000kg= 1Mg

u1 =initial velocity of freight car = 108km/h,

m2 = mass of stationary freight car = ?, this the unknown we are finding

u2 = initial velocity of

m2 = 0, because it is at rest,

v1= final velocity of m1,

v2= final velocity of m2

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v1=v2= 36km/h

substituting valves in expression give

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3 years ago
A small object carrying a charge of -4.00 nC is acted upon by a downward force of 24.0 nN when placed at a certain point in an e
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Answer:

E  = -6 \  N/C

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

Explanation:

From the question we are told that

   The charge on the small object is Q = -4.00 \ nC =  -4.00 *10^{-9} \  C

   The force is  F  =  24  \ nN  =  24 *10^{-9} \  N

    Generally the magnitude of the electric  field is mathematically represented as

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Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

 

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