Metal
On the periodic table its atomic number is 89
The Semi-metals aka the metalloids are atomic umbers 5,14,32,33,51,52,and 85
The Metals are everything that is located to the left of the metalloids excluding Hydrogen(H) and Helium (He)
Everything to the right of the metalloids are non-metals including Hydrogen (H) and Helium (He)
You can take two liquids of different densities (how much mass is in a given volume) and pour them into a funnel. An example is oil and water. When the mixture settles, the denser liquid will be at the bottom, and drips through the funnel first. This is a separation that you can just let occur naturally.
The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~
Answer:
Growth rate
Explanation:
The responding variable, also known as the DEPENDENT VARIABLE, is the variable that responds to changes or manipulations made to another variable (independent or manipulable variable) in the experiment. It is the measured variable of an experiment.
According to the hypothesis provided for this investigation, the scientist wants to determine if the amount of fertilizer plants of the same species receive will affect their growth rate when planted in the same condition. This shows that the independent variable is the amount of fertilizer to be used while the RESPONDING VARIABLE OR DEPENDENT VARIABLE is the GROWTH RATE OF THE PLANTS because it responds to the amount of fertilizer.
Hi, the question has some missing part. The complete question should be " If the 
of 
is 3.74 and the pH of an 
solution is 3.89, it means that -
(a) ![[HCHO_{2}]=[NaCHO_{2}]](https://tex.z-dn.net/?f=%5BHCHO_%7B2%7D%5D%3D%5BNaCHO_%7B2%7D%5D)
(b) ![[HCHO_{2}]> [NaCHO_{2}]](https://tex.z-dn.net/?f=%5BHCHO_%7B2%7D%5D%3E%20%5BNaCHO_%7B2%7D%5D)
(c) ![[HCHO_{2}]< [NaCHO_{2}]](https://tex.z-dn.net/?f=%5BHCHO_%7B2%7D%5D%3C%20%20%5BNaCHO_%7B2%7D%5D)
Which of the options are true?"
Answer: Option (c) is true.
Explanation:
is an weak acid-conjugate base buffer. Hence, in accordance with Henderson-Hasselbalch equation-
![pH=pK_{a}(HCHO_{2})+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%28HCHO_%7B2%7D%29%2Blog%28%5Cfrac%7B%5BCHO_%7B2%7D%5E%7B-%7D%5D%7D%7B%5BHCHO_%7B2%7D%5D%7D%29)
Here, pH = 3.89, of = 3.74
So, ![3.89=3.74+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})](https://tex.z-dn.net/?f=3.89%3D3.74%2Blog%28%5Cfrac%7B%5BCHO_%7B2%7D%5E%7B-%7D%5D%7D%7B%5BHCHO_%7B2%7D%5D%7D%29)
or, ![\frac{[CHO_{2}^{-}]}{[HCHO_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCHO_%7B2%7D%5E%7B-%7D%5D%7D%7B%5BHCHO_%7B2%7D%5D%7D)
= 1.41 (>1)
So, ![[CHO_{2}^{-}]> [HCHO_{2}]](https://tex.z-dn.net/?f=%5BCHO_%7B2%7D%5E%7B-%7D%5D%3E%20%5BHCHO_%7B2%7D%5D)
or, ![[NaCHO_{2}]> [HCHO_{2}]](https://tex.z-dn.net/?f=%5BNaCHO_%7B2%7D%5D%3E%20%5BHCHO_%7B2%7D%5D)
Hence, option (c) is correct.
