Q = m c T
c= 0.140 j/(g x °c)
m= 250.0g
T =52
hope you can solve it now
The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:

Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
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Answer:
5.119 *10^25
Explanation:
1 mole = 6.022 * 10^23

the moles cancel out so you get
85 * (6.022*10^23)
Plug that into the calculator so you get:
5.119 *10^25