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disa [49]
2 years ago
7

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the

bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 °C, if the moles are constant?
Chemistry
1 answer:
alexdok [17]2 years ago
7 0

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.4 atm

P_2 = final pressure of gas = 1.0 atm

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 15^oC=273+15=288K

T_2 = final temperature of gas = 27^oC=273+27=300K

Now put all the given values in the above equation, we get:

\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}

V_2=625mL

Therefore, the volume of the bubble is, 625 mL

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choli [55]

Answer: $46.98

Explanation:

The distance to drive to Los Angeles from San Francisco is 405 miles. Since the car get 25 miles per gallon of gas, for 405 miles, the car will use:

= 405/25 = 16.2 gallons

Since the cost of gasoline is $2.90 a gallon and the car will use 16.2 gallons. The cost will be:

= $2.90 × 16.2 gallons

= $46.98

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2 years ago
Insoluble compounds in a chemical reaction are called?
Rzqust [24]
They are called precipitates. 
8 0
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A gold ring with a mass of 16g was dropped in the snow and its temperature dropped from 35°C to 0°C. How much heat was released
Luda [366]

Answer:

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Explanation:

just finished the test

4 0
2 years ago
HCI + NaOH --> NaCl + H 20
Vikki [24]

Answer:

option D is correct

Explanation:

no of moles in 3 grams of HCL=3/36=0.08

if 1 mole of HCL require 1 mole of NaOH then 0.08 moles required 0.08 moles of NaOH

mass of 0.08 moles of NaOH=moles*molar mass=0.08*40=3.2 grams

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6 0
2 years ago
The organic compound di‑n‑butyl phthalate, C 16 H 22 O 4 ( l ) , C16H22O4(l), is sometimes used as a low‑density ( 1.046 g ⋅ mL
damaskus [11]

Answer:

36.63 Torr

Explanation:

You need to use two expressions, one for pressure and the other with the relation of density and height of the column.

For the pressure:

P = h * d * g  (1)

h is height.

d density

g gravity

The second expression put a relation between the densities and height of the column so:

d1/d2 = h1/h2 (2)

let 1 be the phthalate, and 2 the mercury.

Let's calculate first the relation of density:

d1/d2 = 13.53 / 1.046 = 12.93

Now with the first expression, we can calculate the pressure so:

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We have two compounds so,

h1d1g = h2d2g ---> gravity cancels out

From here, we can solve for h2:

h2 = h1*(d1/d2)

replacing:

h2 = 459 / 12.53

h2 = 36.63 mm

1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr

8 0
2 years ago
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