of oxygen at STP would be required to react completely with 38.8g of propane.
<u>Given that :</u>
molar mass of propane = 44 g/mol
mass of propane = 38.8 g
∴ Moles present in 38.8 g of propane = 
= 0.88 mole
<u>applying rule of balanced equations </u>
1 mole of propane = 5 moles of oxygen
0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen
Note : volume of 1 mole of oxygen at STP = 
∴Total volume of oxygen required at STP = 22.4 * 4.4 =
Hence we can conclude that the volume of oxygen at STP required to react completely
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Resources found in lithosphere: gold and iron etc
Resources found in atmosphere: Water vapor, gases etc.
K(eq) = concentration of products/concentration of reactant = [Cu+2] / [Ag+]^2
Activity of pure solid and liquid is taken as 1.
Hence last option is correct.
Hope this helps, have a great day ahead!
I hope this helps you alot
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The valence electron does the halogens possess are 7
- Valence electrons are found in the outermost energy level of an atom
- They are involved in the formation of chemical bonding with other atoms.
- The halogens elements are found in group 17 on the periodic table
- The halogens include fluorine, chlorine, bromine, iodine and astatine.
- They have seven valence electrons, so they are extremely reactive as they only need one more to fill their outer shell.
- By octet rule we can say that the electron with 8 outer most shell is full and stable.
Hence the halogens posses 7 valence electron
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Answer:
The final volume is 3.07L
Explanation:
The general gas law will be used:
P1V1 /T1 = P2V2 /T2
V2 =P1 V1 T2 / P2 T1
Give the variables to the standard unit:
P1 = 345 torr = 345 /760 atm = 0.4539atm
T1 = -15°C = -15 + 273 = 258K
V1 = 3.48L
T2 = 36°C = 36+ 273 = 309K
P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm
V2 = ?
Equate the values into the gas equation, you have:
V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258
V2 = 488.0877 /158.8764
V2 = 3.07
The final volume is 3.07L
