Answer:
Telophase can be described as the phase in which there are complete haploid set of chromosomes. The chromosomes have two sister chromatids. A cleavage furrow is formed from the centre of the cell which divides the cell into two parts. Telophase is the final stage of the process of division of a cell.
Cytokinesis can be described as a process by which the cytoplasm between the two new daughter cells separate.
Answer:
The arteriole that delivers blood to the glomerulus is the Afferent arteriole
Answer:
1. IV: Time the Bell is rang DV: Time it takes to learn the task
2. IV: Nitrogen fertilizers DV: Diversity of fish
3. IV: Time of radiation DV: Percentage of successful germination
Explanation:
The independent variable of an experiment refers to the variable that the experimenter manipulates or changes in order to effect a measurable response in the dependent variable while the dependent variable is the variable that responds to the changes made to the independent variable.
1. In scenario 1, the TIME THE BELL RINGS is the independent variable because that is what the experimenter controls or has power to change. On the other hand, the dependent variable is the TIME IT TAKES TO LEARN THE TASK because it is the measured variable that responds to the independent variable.
2. In scenario 2, the USE OF NITROGEN FERTILIZER is the independent variable while the DIVERSITY OF FISH is the dependent variable.
3. In case 3, the TIME OF RADIATION is the independent variable while the PERCENTAGE OF SUCCESSFUL GERMINATION is the dependent variable.
Answer:
C. +23.1 kJ/mol
Explanation:
the formula to use to calculate the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells is:
ΔGt = RTIn
+ ZFΔV
let's list the values of the data we are being given in the question to make it easier when solving it.
Z= 1
F= 96500C (faraday's constant)
ΔV= 160mV = 0.160V
R= 8.314( constant)
T= 15ºC ( converting our degree Celsius into kelvin, we will have 273.15k+ 15 = 288.15K)
∴ T= 288.15K
Putting it all together in the formula, we have:
ΔGt = 8.314 × 288.15 × 2.303 log
+ 1 × 96500 × 0.160
ΔGt = 5517.25
+15440
ΔGt = 5517.25
+15440
Given that the pH differential gradient across the membrane is 1.4pH units. It implies that;
ΔGt = 5517.25 × 1.4 + 15440
= 7724.15 +15440
= 23164.15 Joules/moles
= +23.1 KJ/mole