3028 molucoles bro it’s lit
Answer:
i think
they are used to male the animal grow
Answer:
B. Na and Li
Both are group I elements.
Answer:
The new partial pressures after equilibrium is reestablished:



Explanation:

At equilibrium before adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
The expression of an equilibrium constant is given by :


At equilibrium after adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
Total pressure of the system = P = 263.0 Torr




At initail
(13.2) Torr (32.8) Torr (13.2) Torr
At equilbriumm
(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr


Solving for x;
x = 6.402 Torr
The new partial pressures after equilibrium is reestablished:


