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Makovka662 [10]
3 years ago
11

The first letter of a chemical symbol is capitalized.true or false

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
5 0
True because it has to be an capital letter because it’s scientific
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Predict the products of the following reaction and balance the equation: ___Na2CO3(aq) + ___HCl (aq) ->
zheka24 [161]

Answer:

RxN: Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)

NIE: n/a

Explanation:

Step 1: Predict (Double Replacement)

Na₂CO₃ (aq) + HCl (aq) → NaCl (aq) + H₂CO₃ (aq)

Step 2: Balance

Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)

Step 3: Write Total Ionic Equation

2Na⁺ (aq) + CO₃²⁻ (aq) + 2H⁺ (aq) + 2Cl⁻ (aq) → 2Na⁺ (aq) + 2Cl⁻ (aq) + 2H⁺ (aq) + CO₃²⁻ (aq)

Step 4: Remove Spectator Ions

- Na⁺

- CO₃²⁻

- H⁺

- Cl⁻

Step 5: Write Net Ionic Equation

None.

3 0
3 years ago
What forms when iron-53 decays?
amm1812
It depends on the type of decay that is taking place if its a β+ it will decay into Mn-52 β- decays into Co-59
3 0
4 years ago
Read 2 more answers
Why is cellular respiration important?
8_murik_8 [283]
A because b is for photosynthesis
5 0
3 years ago
Calculate the molecular mass of Co(NO3)2<br>with steps please
Nana76 [90]

Answer:

182.933~ \text{g mol}^{-1}

Explanation:

\text{Atomic mass of cobalt(Co)} = 58.933~u\\\\\text{Atomic mass of nitrogen(N)}= 14~u\\\\\text{Atomic mass of oxygen(O)}=16~u\\\\\text{Molar mass of}~ \text{Co}\left(\text{NO}_3} \right)_2 = 58.933 + 2(14 +16 \times 3)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(58.933 + 124)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=182.94~ \text{g mol}^{-1}

4 0
2 years ago
A salt bridge: Question 3 options: provide a pathway through which the electrons travel from the cathode to the anode. provide a
Vesnalui [34]

Answer:

The correct option is: provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.

Explanation:

A salt bridge is a U-shaped glass tube that is used in a voltaic cell or galvanic cell to connect the oxidation and reduction half-cells and complete the electric circuit.

<em>It allows the ions to pass through it, thus preventing the accumulation of charge on the anode and cathode as the chemical reaction proceeds.</em>

<u />

Therefore, the correct option is: <u>provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.</u>

5 0
3 years ago
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