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denpristay [2]
3 years ago
6

What is the chemical formula for the ionic compound calcium chloride?

Chemistry
2 answers:
Juliette [100K]3 years ago
6 0

The answer to your question is,

B) CaCl2

-Mabel <3

forsale [732]3 years ago
3 0
B) is the accurate answer for the chemical formula
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a sample of gold required 2.1200j of heat to melt it from room temperature, 22.0 degrees celsius to its melting point, 1064.4 de
ElenaW [278]

Mass of Gold = 267.165 ×  0.01552494829

⇒ 4.1477228099

The amount of heat(q) required to raise m grams of a substance-specific C from T1 to T2 is given by

q=m C (T2-T1) ........1

Given : q= 2.1200 J

the initial temperature of gold, T1 = 22.0Celcius

the final temperature of gold, T2 = 1064.4Celcius

specific heat of gold = 0.131

putting values in eq 1:

⇒ 2.1200 = m × 0.131 × (1064.4-22)

⇒ 2.1200 = m × 0.131 × 1042.4

⇒ 2.1200 / 136.5544

⇒ 0.01552494829

Since 1g= 0.01552494829 Pounds

Mass of Gold = 267.165 ×  0.01552494829

⇒ 4.1477228099

Learn more about temperature here: brainly.com/question/11464844

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7 0
1 year ago
How will the volume of a gas be affected if the pressure is tripled, but the temperature remains the same?
dangina [55]

Answer:

Volume of the gass will decrease by three times of the original volume

Explanation:

Volume is inversly propotional to the pressure applied on it.

4 0
3 years ago
Read 2 more answers
Determina el pH de una solución si la concentración de H es 3.5 x 10 molar, e indicar si es acido o bas
erastovalidia [21]

Answer:

Explanation:

IT'S FOR NOW, PLEASE DELIVER IT TODAY !!! I NEED HELP IT'S CHEMICAL WORK...

5 0
3 years ago
In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
blsea [12.9K]

Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

% composition = ?

Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition Cu = (2.50 g / 3.12 g)×100

% composition Cu = 0.80 ×100

% composition Cu = 80.1%

For oxygen:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition O = (0.62 g / 3.12 g)×100

% composition O = 0.199 ×100

% composition O = 19.9%

5 0
2 years ago
1. Three different observers measure the melting point of a substance and agree on the
Naddik [55]

d. precise but not accurte

7 0
3 years ago
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