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vesna_86 [32]
3 years ago
15

What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t

o make a 500.0 ml solution?
Chemistry
1 answer:
const2013 [10]3 years ago
4 0

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

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3 years ago
use the equation 2C4H10 +13O2-->8CO2+10H2O to find how many moles of oxygen would react with .425 mol C4H10
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2C4H10 + 13O2  →  8CO2 + 10H2O Since the equation is balanced, we can set up a proportion: 13 moles of O2 react with 2 moles of C4H10x  moles of O2 react with 0.425 moles of C4H10 13 → 2x → 0.425 x = 13 * 0.425 / 2 = 2.7625 <span>2.7625 moles of O2 react with 0.425 moles of C4H10</span> 
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