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3 years ago

15

What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t

o make a 500.0 ml solution?

1 answer:

const2013 [10]3 years ago

4 0

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

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