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nata0808 [166]
2 years ago
15

WHAT DID HE DO WRONG 333/1,000 = 0.333 =0.3

Mathematics
2 answers:
san4es73 [151]2 years ago
6 0

Answer:

He dropped 2 of the 3 in the last simplification and you can't do that. You can't just get rid of two of the values that make up the number. The farthest you are able to simplify is 0.333.

Montano1993 [528]2 years ago
3 0

He thought the 0.333 was continuing, so he rounded. However, the answer ISN'T continuing, so he shouldn't round.

Hope this helps!

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Which one is right ???????
wel
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Helma wants to find the volume of the right rectangular prism shown below. Which equation could Helma use to find V, the volume
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Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
3 years ago
Plz help.<br> find the solution for:<br> 9-3 | x-2 | = 4<br> will give brainliest.
meriva

answer:

x=1/3

x=11/3

STEP 1:

Rearrange this Absolute Value Equation

Absolute value equalitiy entered

-3|x-2|+9 = 4

Another term is moved / added to the right hand side.

To make the absolute value term positive, both sides are multiplied by (-1).

3|x-2| = 5

STEP 2:

Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is 3|x-2|

For the Negative case we'll use -3(x-2)

For the Positive case we'll use 3(x-2)

STEP 3:

Solve the Negative Case

-3(x-2) = 5

Multiply

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Divide both sides by 3

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Multiply both sides by(-1)

x = (1/3)

Which is the solution for the Negative Case

STEP 4:

Solve the Positive Case

3(x-2) = 5

Multiply

3x-6 = 5

Rearrange and Add up

3x = 11

Divide both sides by 3

x = (11/3)

Which is the solution for the Positive Case

giving us  x=1/3 or x=11/3

allso if u can i need help with a thing so plese help, i would aprestiate it

brainly.com/question/25340824

7 0
2 years ago
Read 2 more answers
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