Answer:
Position of object is;
s(t) = 4t³/3 + 3t + 1
Explanation:
We are told that the velocity has an expression;
v(t) = 3.00 m/s + ( 4.00 m/s³)t²
Now, to get the expression for the position(s(t)) of the object, we have to integrate the velocity expression. Thus;
s(t) = ∫3 + 4t²
s(t) = 3t + 4t³/3 + c
Now, we were told that at x = 1.00 m, time t = 0.000 s
Thus, plugging the values in;
1 = 3(0) + 4(0³/3) + c
c = 1
Thus,the expression for the position of the object is;
s(t) = 4t³/3 + 3t + 1
The answer is : 35 to 52 minutes.
Hope this helps!
Please give Brainliest!
Answer:
t=27725.8minutes
Explanation:
To determinate use the law the change of volume in determinate time is derivate so:
The flow in is zero and the flow out is modeling with V as the volume out in the volume of the lake in the reason of change.
Integrate to get the volume function
The find the constant C in the time t=0 the volume is knowing so:
The volume is 1 part per million so:
The ideal spring equation is
Stretch = K times Force .
This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by π or
any other number, you multiply the stretch by the same number.
So you can always write a proportion for a spring:
Stretch₁ / Force₁ = Stretch₂ / Force₂ .
Part A:
In Part-A of this question, the force is increased to (2.5 / 2.0) = 1.25 times .
So the stretch is also increased to 1.25 times .
(1.25) x (6.1 cm) = 7.625 cm .
Answer:
force and leverage distance
Explanation:
the formula for torque if = force x distance
(the distance above is the leverage distance on the crow bar)
therefore if there is an increase in either the torque or the leverage distance, or both, the torque exerted by the crow bar also increases.
for example
- lets assume a force of 5 n is applied on the crow bar with a leverage distance of 2 m.
the torque = 5 x 2 = 10 N.m
- but if the force was increased to 7 N
torque = 7 x 2 = 12 N.m
from the illustration above, we can see that the torque increased with an increase in force. There would also be an increase in torque if the distance were to be increased.
