A bicycle rim has a diameter of 0.65 m and a moment of inertia, measured about its center, of 0.21 kg⋅m2What is the mass of the
1 answer:
Answer:
m = 1.99 kg = 2 kg
Explanation:
The moment of inertia of a bicycle rim about it's center is given by the following formula:
where,
I = Moment of Inertia of the Bicycle Rim = 0.21 kg.m²
r = Radius of the Bicycle Rim = Diameter of the Bicycle Rim/2
r = 0.65 m/2 = 0.325 m
m = Mass of the Bicycle Rim = ?
Therefore,
<u>m = 1.99 kg = 2 kg</u>
You might be interested in
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.
and,
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.
=
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.