Question

A fish appears to be 2.00 m below the surface of a pond (nwater = 1.33) when viewed almost directly above by a fisherman. What is the actual depth of the fish?

Answer 1

Explanation:

The given data is as follows.

     Apparent depth = 2.00 m,  refractive index = 1.33

It is known that formula to calculate real depth is as follows.

   The refractive index = $\frac{\text{real depth}}{\text{apparent depth}}$

or,       real depth = refractive index × apparent depth

Now, putting the given values into the above formula as follows.

               real depth = 1.33 × 2

                                 = 2.66 m

Thus, we can conclude that the actual (real) depth of the fish is 2.66 m.

Answer 2

Answer:

Actual depth = 2.66 m

Explanation:

Given:

Apparent depth = Depth of fish as seen below the surface of water = $D_{a}$ = 2 m

Refractive index of water = n = 1.33

Actual depth is related to the apparent depth as follows:

n = $D_{r}$ / $D_{a}$

⇒ Actual depth = $D_{r}$ = n × $D_{a}$

                                                      = (1.33) ( 2 ) = 2.66 m