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kupik [55]
3 years ago
7

The torque exerted by a crowbar on an object increases with increased _______.

Physics
1 answer:
Fofino [41]3 years ago
3 0

Answer:

force and leverage distance

Explanation:

the formula for torque if = force x distance

(the distance above is the leverage distance on the crow bar)

therefore if there is an increase in either the torque or the leverage distance, or both, the torque exerted by the crow bar also increases.

for example

  • lets assume a force of 5 n is applied on the crow bar with a leverage distance of 2 m.

        the torque = 5 x 2 = 10 N.m

  • but if the force was increased to 7 N

        torque = 7 x 2 = 12 N.m

from the illustration above, we can see that the torque increased with an increase in force. There would also be an increase in torque if the distance were to be increased.

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ehidna [41]

Answer:

a = -1.6\ m/s^2

Explanation:

<u>Accelerated Motion</u>

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\displaystyle a=\frac{v_f-v_o}{t}

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3 0
3 years ago
Each piston of an engine makes a sharp sound every other revolution of the engine. How fast is a race car going if its eight-cyl
goldfiish [28.3K]

Answer:

93.75 m/s

Explanation:

Given:

The frequency of the sound = 750 Hz

The number of pistons making the sound = 8

Revolutions made by the engine = 2000 revolutions/ km

Thus,

the frequency of sound by 1 piston = 750 / 8  = 93.75 Hz

also, it is given that for every other revolution sound is made.

thus, for every 2 revolution sound is made

therefore,

Number of revolutions per second = 93.75 Hz × 2 = 187.5 rev/s

Now,

the speed of the car will be calculated as:

= Number of revolutions per second / Revolutions made by the engine

or

The speed of the car = \frac{187.5\ rev/s}{2000\ rev/km}

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The speed of the car = 0.09375 km/s = 93.75 m/s

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Explain how the data collected and the calculations for the first and second resonance points in today's experiment would change
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tssths

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