Question

One mole of copper(ii) sulfate, cuso4, contains ________ o atoms.

Answer 1

Answer : One mole of copper(II)sulfate contains $24.088\times 10^{23}$ number of oxygen atoms.

Solution :

As we know that, 1 mole of contains $6.022\times 10^{23}$ number of atoms.

In $CuSO_4$, there are 1 number of copper atom, 1 number of sulfur atom and 4 number of oxygen atoms.

As 1 mole of copper(II)sulfate contains $4\times 6.022\times 10^{23}=24.088\times 10^{23}$ number of oxygen atoms.

Therefore, one mole of copper(II)sulfate contains $24.088\times 10^{23}$ number of oxygen atoms.

Answer 2

According  to  avogadro   constant,  the  number  of  units  in  one  mole  of  any  substance   contain  6.022  x10  ^23  atoms

therefore  the  number  of  o  atoms  in   one  mole  of    CuSO4  =  6.022 x 10 ^ 23