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Fantom [35]
3 years ago
6

What temperature in degrees c is the freezing point of water?

Chemistry
1 answer:
guajiro [1.7K]3 years ago
5 0
The freezing point of water is 0° C. The Celsius (centigrade) scale is based off of water, with the freezing point at 0° and the boiling point at 100°. (Google will probably tell you this in 10 seconds, then you wouldn't have had to wait 7 hours!)
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A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
The ΔHcomb value for anethole is -5539 kJ/mol. Assume 0.840 g of anethole is combusted in a calorimeter whose heat capacity (Cal
bonufazy [111]

Answer:

Final temperature of calorimeter is 25.36^{0}\textrm{C}

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.840 g of anethole = \frac{0.840}{148.2}moles of anethole = 0.00567 moles of anethole

1 mol of anethole releases 5539 kJ of heat upon combustion

So, 0.00567 moles of anethole release (5539\times 0.00567)kJ of heat or 31.41 kJ of heat

6.60 kJ of heat increases 1^{0}\textrm{C} temperature of calorimeter.

So, 31.41 kJ of heat increases (\frac{1}{6.60}\times 31.41)^{0}\textrm{C} or 4.76^{0}\textrm{C} temperature of calorimeter

So, the final temperature of calorimeter = (20.6+4.76)^{0}\textrm{C}=25.36^{0}\textrm{C}

3 0
3 years ago
Which one is the right one dont mine the one i put that one is wrong
Degger [83]

Answer: The answer is B

Explanation:

7 0
2 years ago
How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you
SOVA2 [1]

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = \frac{\text{No. of moles}}{\text{Volume}}

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = 0.5 M \times 1 L

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = 0.5 mol \times 132.119 g/mol

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0
3 years ago
What is the maximum vertical distance between the line y = x 2 and the parabola y = x2 for −1 ≤ x ≤ 2?
Mrac [35]

x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points

f(x)=x+2−x^2

df/dx=1–2x

and that is zero (indicating a maximum) at x=1/2

So the maximum distance is f(1/2)=2.5–0.25=2.25

learn more about maximum distance between curves here:

brainly.com/question/1603866

#SPJ4

5 0
2 years ago
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