Question

For both circuits: Determine the potential difference on and the current through each resistor. Show your work and then check your answer with PhET

Answer 1

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: This question is incomplete and lacks the necessary diagram of the circuits to solve for this question. However, I have found similar question on the internet and dragged the diagrams out of it. I have attached the diagrams of the circuits for your ease. It has two circuits to be solved. Attachment 1 refers to first circuit and Attachment 2 refers to second circuit.

Solution:

We are asked to find the potential difference and current through each resistor.

So,

Calculations for Circuit 1: Please refer to Attachment 1

First we need to find the Resistance:

Req = $\frac{9 . 6}{9+6} +3$

R = 6.6 Ohm

Now, we know that:

V = IR

So,

I = V/R

V = 12 V

I = 12 V/ 6.6 ohm

I = 1.82 Amperes.

Now,

The Potential Difference through 3 ohm resistor:

P.D = $V_{3}$ = 1.82 x 3

$V_{3}$ = 5.45 V

Now,

The Potential Difference through 6 ohm and 9 ohm resistor:

$V_{6/9}$ =  12V - 5.45V

$V_{6/9}$ =  6.545V

Now,

The current through 6 ohm is:

$I_{6}$ = $\frac{6.545}{6}$

$I_{6}$ = 1.09 A

Now,

The Current through 9 ohm is:

$I_{9}$  = $\frac{6.545}{9}$

$I_{9}$  = 0.72 A

Similarly,

Calculations for Circuit 2: Please refer to attachment 2:

Req = $\frac{(30+50).90}{90+(30+50)} +20$

Req = 62.35 ohm

I = V/R

I = 12 V/ 62.35ohm

I = 0.192 Amperes.

Now,

The The Potential Difference through 20 ohm resistor:

$V_{20}$ = 20 x 0.192

$V_{20}$ = 3.849 V

Now,

The The Potential Difference through 90 ohm resistor:

$V_{90/(30+50)}$ = 12 - 3.849

$V_{90/(30+50)}$ = 8.150

Now,

The Current through 90 ohm is:

$I_{90}$  = 8.1509/90

$I_{90}$ = 0.0905 Amperes

Now,

The Current through 30 and 50 ohm is:

$I_{30/50}$ = 0.192 - 0.0905

$I_{30/50}$  = 0.101 A

Now,

The Potential Difference through 50 ohm resistor:

$V_{50}$ = 50 x 0.101

$V_{50}$  = 5.094 V

The Potential Difference through 30 ohm resistor:    

$V_{30}$ = 30 x  0.101

$V_{30}$ = 3.0566 V