Answer:
W=16.58J
Explanation:
initial information we have
work:
stretched distance:
from this, we can find the value of the constant of the spring k, with the equation for work in a spring:
substituting known values:
and clearing for k:
and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:
and using the same formula for work, with the value of k that we just found:
Given,
The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m
The initial speed of the water, v₁=12.5 m/s
The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m
From the continuity equation,
Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.
On substituting the known values,
Thus, the flow rate of the water at the later position is 5.99 m/s