The power expended is 500 W
Explanation:
First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

where
m = 50 kg is the mass of the man
is the acceleration of gravity
is the change in height
Substituting,

Now we can calculate the power expended, which is given by

where
W = 2500 J is the work done
t = 5 s is the time elapsed
Substituting, we find

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Answer:
(a) 42 N
(b)36.7 N
Explanation:
Nomenclature
F= force test line (N)
W : fish weight (N)
Problem development
(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed
We apply Newton's first law of equlibrio because the system moves at constant speed:
∑Fy =0
F-W= 0
42N -W =0
W = 42N
(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²
We apply Newton's second law because the system moves at constant acceleration:
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
∑Fy =m*a
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
F-W= ( W/9.8 )*a
42-W= ( W/9.8 )*1.41
42= W+0.1439W
42=1.1439W
W= 42/1.1439
W= 36.7 N
Answer:
C. Experimental Probability
Explanation:
The empirical (or experimental) probability means the event that arise and depend how the event arise when the data is collected from an experiment in a more no of trials. It would be depend upon the direct observation. Here each and every observation in an experiment is known as trial
So the probability that depend upon the experiment observation is known as the experimental probability
Hence, the option c is correct
Answer:
The work done on the gas = 2PV
Explanation:
In this question, we need to apply the basic gas laws to determine the word done.
For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.
So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.
As we know that, the work done on the gas is equal to the area under the curve.
W = Area of the triangle
W = 0.5 x ( base) x ( height)
W = 0.5 x (BC) x (AC)
W = 0.5 x (3V-V) x (3P-P)
W = 2PV
Hence, the work done on the gas = 2PV