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3 years ago

The photo shows an ecosystem.

Physics

2 answers:

mixer [17]3 years ago

4 0

Answer:

because the animal with sweat gland it easy to adopt the environment

Nimfa-mama [501]3 years ago

4 0

Answer:

A and B

Explanation:

The ecosystem is cold and the mammals need heat.

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A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago

Geologists apply various methods to study the layers of the Earth. Which of the following is NOT a method used to study the Eart

77julia77 [94]

Answer:

A. Scientists use seismic computer models to measure the atmospheric conditions above the Earth's crust

Explanation:

why would use atmosphere to study the layers of earth? dont think thats possible

8 0

3 years ago

An atom's mass number equals the number of

Alex73 [517]

Answer:

Explanation:

Mass number consist of number of proton and neutron in an atom

8 0

3 years ago

A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 270 kg · m2 and is rotating at 8.0 rev/min about a

Arte-miy333 [17]

Answer:

$\dot n = 6.042\,rpm$

Explanation:

The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:

$(270\,kg\cdot m^{2})\cdot \left(8\,rpm\right) = [270\,kg\cdot m^{2}+(27\,kg)\cdot (1.80\,m)^{2}]\cdot \dot n$

$\dot n = 6.042\,rpm$

3 0

3 years ago

A 23.0 kg child is riding a playground merry-go-round that is rotating at 30.0 rpm. What centripetal force, in N, must she exert

sammy [17]

Answer:

The value is $F = 454 \ N$

Explanation:

From the question we are told that

The mass of the child is $m = 23.0 \ kg$

The angular velocity is $w = 30 \ rpm = \frac{2 \pi * 30 }{60} = 3.142 \ rad/s$

The distance from the center is $r = 2.0 \ m$

Generally the centripetal force is mathematically represented as

$F = m * w^2 * r$

=> $F = 23 * 3.142 ^2 * 2$

=> $F = 454 \ N$

5 0

3 years ago