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Serhud [2]
3 years ago
14

1) A common experiment to determine the relative reactivity of metallic elements is to place a pure sample of one metal into an

aqueous solution of a compound of another metallic element. If the pure metal you are adding is more reactive than the metallic element in the compound, then the pure metal will replacethe metallic element in the compound. For example, if you place a piece of pure zinc metal into a solution of copper(II) sulfate, the zinc will slowly dissolve to produce zinc(II) sulfate solution, and the copper(II) ion of the copper(II) sulfate will be converted to metallic copper. Write the unbalanced equation for this process. (Include states-of-matter under the given conditions in your answer.)
Chemistry
2 answers:
Annette [7]3 years ago
7 0

Answer: Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

Explanation:-

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

As zinc is more reactive than copper, it could easily displace copper from its aqueous solution and thus leads to formation of zinc (II) sulfate and pure copper.

The chemical reaction can be represented as :

Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

The phases are represented as (s) for solid sate, (l) for liquid state, (g) for gaseous state and (aq) for aqueous state.

Furkat [3]3 years ago
7 0

Answer:

Zn(s) + CuSO₄(aq) ⇄ ZnSO₄(aq) + Cu(s)

Explanation:

Metal zinc reacts with a solution of copper (II) sulfate to produce aqueous zinc sulfate and metallic copper. This is a displacement reaction according to the following molecular equation.

Zn(s) + CuSO₄(aq) ⇄ ZnSO₄(aq) + Cu(s)

Zinc is more reactive than copper, so that the latter is displaced from its salt. Since SO₄²⁻ is a spectator ion, we can write the net ionic equation as follows.

Zn(s) + Cu²⁺(aq) ⇄ Zn²⁺(aq) + Cu(s)

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fgiga [73]
The equation is 2 NH3 (g) ⇀↽ N2 (g) + 3 H2 (g) 
Difference in the number of moles delta n = ((3 + 1) - 2) = 4 - 2 = 2 
We have an equation Kp= Kc (R x T) ^ (delta n); R is constant and T = 300 K 
Kp / Kc = (R x T) ^2 Based on the temperature value (300 K), we can conclude that Kp is Larger.
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3 years ago
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stiks02 [169]

Answer:

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Explanation:

6 0
3 years ago
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An ionic bond is a bond
vesna_86 [32]

Answer:

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7 0
3 years ago
A chemist adds 0.60L of a 0.20/molL sodium thiosulfate Na2S2O3 solution to a reaction flask. Calculate the millimoles of sodium
Serggg [28]

Answer:

1.2×10² mmole of Na₂S₂O₃

Explanation:

From the question given above, the following data were obtained:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the number of mole of Na₂S₂O₃ in the solution as illustrated below:

Volume = 0.6 L

Molarity = 0.2 mol/L

Mole of Na₂S₂O₃ =?

Molarity = mole /Volume

0.2 = Mole of Na₂S₂O₃ / 0.6

Cross multiply

Mole of Na₂S₂O₃ = 0.2 × 0.6

Mole of Na₂S₂O₃ = 0.12 mole

Finally, we shall convert 0.12 mole to millimole (mmol). This can be obtained as follow:

1 mole = 1000 mmol

Therefore,

0.12 mole = 0.12 mole × 1000 mmol / 1 mole

0.12 mole = 120 = 1.2×10² mmole

Thus, the chemist added 1.2×10² mmole of Na₂S₂O₃

7 0
3 years ago
Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

Molality = 7.5 m

or        (m=mol/kg)

Molality = 7.5 mol/kg

6 0
3 years ago
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