You can conclude that your substance is a solid because of the slow moving particles and their being little space for those particles to be moving around.
Answer:
1. NO and Br₂
2. 77
3. 8.8
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
The equilibrium constant for this reaction is:
![Kc_{1}=\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]} =1.3 \times 10^{-2}](https://tex.z-dn.net/?f=Kc_%7B1%7D%3D%5Cfrac%7B%5BNOBr%5D%5E%7B2%7D%7D%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%20%3D1.3%20%5Ctimes%2010%5E%7B-2%7D)
1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?
Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.
2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
The equilibrium constant is:
![Kc_{2}=\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}} =\frac{1}{Kc_{1}} =77](https://tex.z-dn.net/?f=Kc_%7B2%7D%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%20%3D%5Cfrac%7B1%7D%7BKc_%7B1%7D%7D%20%3D77)
3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)
The equilibrium constant is:
![Kc_{3}=\frac{[NO][Br_{2}]^{1/2} }{[NOBr]} =\sqrt{\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}}} =\sqrt{Kc_{2}} =8.8](https://tex.z-dn.net/?f=Kc_%7B3%7D%3D%5Cfrac%7B%5BNO%5D%5BBr_%7B2%7D%5D%5E%7B1%2F2%7D%20%7D%7B%5BNOBr%5D%7D%20%3D%5Csqrt%7B%5Cfrac%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E%7B2%7D%7D%7D%20%3D%5Csqrt%7BKc_%7B2%7D%7D%20%3D8.8)
Answer: The difference between the electronegativity or (∆EN) of two different atoms indicates the type of bond created.
Explanation: For ionic bond compounds the difference between their electronegativity is 1.7 or greater. Covalent bond compounds have a difference of 0.4 but not greater than 1.7 on their electronegativity.
Answer:
25% thorium will left after 50 days.
Explanation:
Half life:
A nuclear half is the time period of radioactive material in which its amount remain halved.
In given question it is stated that the half life thorium-234 is 25 days. Which means after passing the 25 days the amount of thorium must be halved of original amount.
For example,
If the original concentration was 100%, than after 25 days it will be 50%.
After 50 days amount of thorium left:
Number of half life = T (elapsed) / T half life
Number of half life = 50/25
Number of half life = 2
At first half life amount of thorium left = 100/2 = 50
After second half life amount of thorium left = 50/2 = 25
Total amount decayed = 50+25 = 75
Amount left after 50 days = 100-75 = 25
25% thorium will left after 50 days.
Answer:
so the number of molecules in 8 moles of water is 4.8176×10^24
Explanation:
number of moles=8moles
avogadro's number=6.022×10²³
number of molecules=?
as we know that
substituting the equation
number of moles × avogdro's number=number of molecules
number of molecules=8moles×6.022×10²³
number of molecules=4.8176×10^24
i hope this will help you :)
