1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kondaur [170]
2 years ago
9

How many moles are in 3.72 x 10^27 atoms of iron?

Chemistry
1 answer:
klemol [59]2 years ago
5 0

Answer: There are 0.617 \times 10^{4} moles present in 3.72 \times 10^{27} atoms of iron.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in one mole of a substance.

Hence, moles present in 3.72 \times 10^{27} atoms are calculated as follows.

Moles = \frac{3.72 \times 10^{27}}{6.022 \times 10^{23}}\\= 0.617 \times 10^{4} mol

Thus, we can conclude that there are 0.617 \times 10^{4} moles present in 3.72 \times 10^{27} atoms of iron.

You might be interested in
Which statement BEST explains whether or not matter is conserved in this chemical reaction?
timurjin [86]

Answer:

D:Matter is not being conserved because there are 11 units in the reactants, one C8H8 and 10 O2, and 12 units in the products, eight CO2 and four H2O, so there is also more mass in the products that in the reactants.

Explanation:

searched up

4 0
2 years ago
Read 2 more answers
What does the oxidizing agent do in a redox reaction apex?
densk [106]
Same as balancing a regular chemical reaction! Please see the related question to the bottom of this answer for how to balance a normal chemical reaction. This is for oxidation-reduction, or redox reactions ONLY! These instructions are for how to balance a reduction-oxidation, or redox reaction in aqueous solution, for both acidic and basic solution. Just follow these steps! I will illustrate each step with an example. The example will be the dissolution of copper(II) sulfide in aqueous nitric acid, shown in the following unbalanced reaction: CuS (s) + NO 3 - (aq) ---> Cu 2+ (aq) + SO 4 2- (aq) + NO (g) Step 1: Write two unbalanced half-reactions, one for the species that is being oxidized and its product, and one for the species that is reduced and its product. Here is the unbalanced half-reaction involving CuS: CuS (s) ---> Cu 2+ (aq) + SO 4 2- (aq) And the unbalanced half-reaction for NO 3 - is: NO 3 - (aq) --> NO (g) Step 2: Insert coefficients to make the numbers of atoms of all elements except oxygen and hydrogen equal on the two sides of each half-reaction. In this case, copper, sulfur, and nitrogen are already balanced in the two half-reaction, so this step is already done here. Step 3: Balance oxygen by adding H 2 O to one side of each half-reaction. CuS + 4 H 2 O ---> Cu 2+ + SO 4 2- NO 3 - --> NO + 2 H 2 O Step 4: Balance hydrogen atoms. This is done differently for acidic versus basic solutions. . For acidic solutions: Add H 3 O + to each side of each half-reaction that is "deficient" in hydrogen (the side that has fewer H's) and add an equal amount of H 2 O to the other side. For basic solutions: add H 2 O to the side of the half-reaction that is "deficient" in hydrogen and add an equal amount of OH - to the other side. Note that this step does not disrupt the oxygen balance from Step 3. In the example here, it is in acidic solution, and so we have: CuS + 12 H 2 O ---> Cu 2+ + SO 4 2- + 8 H 3 O + . NO 3 - + 4 H 3 O + --> NO + 6 H 2 O Step 5: Balance charge by inserting e - (electrons) as a reactant or product in each half-reaction. Oxidation: CuS + 12 H 2 O ---> Cu 2+ + SO 4 2- + 8 H 3 O + + 8 e - . Reduction: NO 3 - + 4 H 3 O + + 3 e - --> NO + 6 H 2 O . Step 6: Multiply the two half-reactions by numbers chosen to make the number of electrons given off by the oxidation step equal to the number taken up by the reduction step. Then add the two half-reactions. If done correctly, the electrons should cancel out (equal numbers on the reactant and product sides of the overall reaction). If H 3 O + , H 2 O, or OH - appears on both sides of the final equation, cancel out the duplication also. Here the oxidation half-reaction must be multiplied by 3 (so that 24 electrons are produced) and the reduction half-reaction must by multiplied by 8 (so that the same 24 electrons are consumed). 3 CuS + 36 H 2 O ---> 3 Cu 2+ + 3 SO 4 2- + 24 H 3 O + + 24 e - 8 NO 3 - + 32 H 3 O + + 24 e - ---> 8 NO + 48 H 2 O Adding these two together gives the following equation: 3 CuS + 36 H 2 O + 8 NO 3 - + 8 H 3 O + ---> 3 Cu 2+ + 3 SO 4 2- + 8 NO + 48 H 2 O Step 7: Finally balancing both sides for excess of H 2 O (On each side -36) This gives you the following overall balanced equation at last: 3 CuS (s) + 8 NO 3 - (aq) + 8 H 3 O + (aq) ---> 3 Cu 2+ (aq) + 3 SO 4 2- (aq) + 8 NO (g) + 12 H 2 O (l)


6 0
3 years ago
Read 2 more answers
Construct <br> an isotope has 17 protons 20 neutrons and 18 electrons
ASHA 777 [7]
Add proton + neutrons = Mass 37

Proton is same as your atomic mass= 17

If you go on the periodic table look up 17 and it will give u the letter.
4 0
2 years ago
How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

6 0
3 years ago
What is the # of Electrons in carbon?
Feliz [49]

Answer:

Carbon dioxide (CO2)

Ethene (C2H4)

Methane (CH4)

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the substances are largely ionic nonpolar covalent polar covalent?
    14·1 answer
  • Which statements correctly define factors that contributed to the decline of the Roman Empire? Choose all answers that are corre
    12·2 answers
  • What is volume (chemistry definition)
    13·1 answer
  • The decomposition of N I 3 to form N 2 and I 2 releases − 290.0 kJ of energy. The reaction can be represented as 2N I 3 (s)→ N 2
    9·1 answer
  • Ammonia and gaseous hydrogen chloride combine to form ammonium chloride. NH3+HCL-&gt;NH4CL
    10·1 answer
  • When a base reacts with an acid, the acid/base reaction always producess
    14·1 answer
  • Convert 0.00353 m to its equivalent in picometers.
    13·1 answer
  • 6. What do we call Ethene that has been polymerised?​
    11·1 answer
  • Rank the following atoms and ions from least to greatest ionization energy:
    12·1 answer
  • The graduated cylinder below shows major scale divisions every 5 mL. How should the volume of the liquid be recorded? Use the co
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!