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3 years ago

Which statement is true about the compound ammonium sulfate [(NH4)2SO4] ?

Chemistry

2 answers:

BabaBlast [244]3 years ago

4 0

Answer:

It is a salt of two polyatomic ammonium ions and one polyatomic sulfate ion

Explanation:

Ammonium Sulfate is an ionic compound formed by two polyatomic ions, Ammonium NH+4 and Sulfate SO−4 . ... Therefore, it will take two +1 ammonium ions to balance the one -2 sulfate ion. This will make the formula for Ammonium Sulfate (NH4)2SO4

timurjin [86]3 years ago

4 0

Answer:

A) It is a salt of two polyatomic ammonium ions and one polyatomic sulphate ion.

Explanation:

A polyatomic ion is an ion composed of two or more atoms. Polyatomic ions are covalently bonded groups of atoms with a positive or negative charge caused by the formation of an ionic bond with another ion. They behave as a single unit and are also known as molecular ion.

Ammonium sulphate [(NH4)2SO4] is an ionic compound formed by two polyatomic ions which are NH4^+ and SO4 ^2-

•In order for these two polyatomic ions to bond, the charges must be equal, opposite and give a net charge of zero.

•Since the sulfate ion has the greater charge, we will need two atoms of NH4^+ that will sum up to give a charge 2+ which will balance the 2- coming from the sulfate polyatomic ion.

We will be having something like this:

NH4^+ + NH4^+ ----> 2NH4^ +

Now we have equal number of charges, two positive and two negative charges coming from two ammonium polyatomic ions and one sulfate polyatomic ion.

NH4^+ NH4^+ SO4^2-

This will make the formula for ammonium sulfate to be (NH4)2SO4

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Calculate δg∘rxn and e∘cell for a redox reaction with n = 3 that has an equilibrium constant of k = 4.4×10−2. you may want to re

lapo4ka [179]

a) First, to get ΔG°rxn we have to use this formula when:

ΔG° = - RT ㏑ K

when ΔG° is Gibbs free energy

and R is the constant = 8.314 J/mol K

and T is the temperature in Kelvin = 25 °C+ 273 = 298 K

and when K = 4.4 x 10^-2

so, by substitution:

ΔG°= - 8.314 * 298 *㏑(4.4 x 10^-2)

= -7739 J = -7.7 KJ

b) then, to get E° cell for a redox reaction we have to use this formula:

ΔE° Cell = (RT / nF) ㏑K

when R is a constant = 8.314 J/molK

and T is the temperature in Kelvin = 25°C + 273 = 298 K

and n = no.of moles of e- from the balanced redox reaction= 3

and F is Faraday constant = 96485 C/mol

and K = 4.4 x 10^-2

so, by substitution:

∴ ΔE° cell = (8.314 * 298 / 3* 96485) *㏑(4.4 x 10^-2)

= - 2.7 x 10^-2 V

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2 years ago

In an experiment, marble chips reacted with dilute hydrochloric acid and carbon dioxide gas was given

laiz [17]

Answer:

Explanation:

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2 years ago

The acetic acid/acetate buffer system is a common buffer used in the laboratory. Write the equilibrium equation for the acetic a

hichkok12 [17]

Answer:

CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base or vice versa.

For the acetic acid buffer, CH₃CO₂H is the weak acid and its conjugate base is the ion without H⁺, that is CH₃CO₂⁻. The equilibrium equation in water knowing this is:

<em>In the equilibrium, the acid is dissociated in the conjugate base and the hydronium ion.</em>

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3 years ago

25 POINTS

Rudiy27

EASY AS PIE AND I LIKE PIE

Calcium iodide (CaI2) is an ionic bond, which means that electrons are transferred. In order for Ca to become the ion Ca2+, the calcium atom must lose 2 electrons. (Electrons have a negative charge, so when an atom loses 2 electrons, its ion becomes more positive.) In order for I to become the ion I1−, the iodine atom must gain 1 electron. (When an atom gains an electron, its ion will be more negative.) However, the formula for calcium iodide is CaI2 - there are 2 iodine ions present. This makes sense because the iodine ion has a charge of -1, so two iodine ions have to be present to cancel out the +2 charge of the calcium ion. Therefore, the calcium atom transfers 2 valence electrons, one to each iodine atom, to form the ionic bond.

IF WRONG, SORRY

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3 years ago

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Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha

Aleks04 [339]

Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

$pH = pKa + log \frac{[Base]}{[Acid]}$