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sergey [27]
3 years ago
5

Which statement is true about the compound ammonium sulfate [(NH4)2SO4] ?

Chemistry
2 answers:
BabaBlast [244]3 years ago
4 0

Answer:

It is a salt of two polyatomic ammonium ions and one polyatomic sulfate ion

Explanation:

Ammonium Sulfate is an ionic compound formed by two polyatomic ions, Ammonium NH+4 and Sulfate SO−4 . ... Therefore, it will take two +1 ammonium ions to balance the one -2 sulfate ion. This will make the formula for Ammonium Sulfate (NH4)2SO4

timurjin [86]3 years ago
4 0

Answer:

A) It is a salt of two polyatomic ammonium ions and one polyatomic sulphate ion.

Explanation:

A polyatomic ion is an ion composed of two or more atoms. Polyatomic ions are covalently bonded groups of atoms with a positive or negative charge caused by the formation of an ionic bond with another ion. They behave as a single unit and are also known as molecular ion.

Ammonium sulphate [(NH4)2SO4] is an ionic compound formed by two polyatomic ions which are NH4^+ and SO4 ^2-

•In order for these two polyatomic ions to bond, the charges must be equal, opposite and give a net charge of zero.

•Since the sulfate ion has the greater charge, we will need two atoms of NH4^+ that will sum up to give a charge 2+ which will balance the 2- coming from the sulfate polyatomic ion.

We will be having something like this:

NH4^+ + NH4^+ ----> 2NH4^ +

Now we have equal number of charges, two positive and two negative charges coming from two ammonium polyatomic ions and one sulfate polyatomic ion.

NH4^+ NH4^+ SO4^2-

This will make the formula for ammonium sulfate to be (NH4)2SO4

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What is the percent composition of NaHCO3?
zhuklara [117]

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

8 0
3 years ago
Please help me:) thanks!
Cloud [144]

Answer:

2Cl2 has 4 atoms

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CaCO3 has 5 atoms

Explanation:

4 0
2 years ago
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Answer:

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Answer:

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Explanation:

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Explanation:

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