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3 years ago

Which statement is true about the compound ammonium sulfate [(NH4)2SO4] ?

Chemistry

2 answers:

BabaBlast [244]3 years ago

4 0

Answer:

It is a salt of two polyatomic ammonium ions and one polyatomic sulfate ion

Explanation:

Ammonium Sulfate is an ionic compound formed by two polyatomic ions, Ammonium NH+4 and Sulfate SO−4 . ... Therefore, it will take two +1 ammonium ions to balance the one -2 sulfate ion. This will make the formula for Ammonium Sulfate (NH4)2SO4

timurjin [86]3 years ago

4 0

Answer:

A) It is a salt of two polyatomic ammonium ions and one polyatomic sulphate ion.

Explanation:

A polyatomic ion is an ion composed of two or more atoms. Polyatomic ions are covalently bonded groups of atoms with a positive or negative charge caused by the formation of an ionic bond with another ion. They behave as a single unit and are also known as molecular ion.

Ammonium sulphate [(NH4)2SO4] is an ionic compound formed by two polyatomic ions which are NH4^+ and SO4 ^2-

•In order for these two polyatomic ions to bond, the charges must be equal, opposite and give a net charge of zero.

•Since the sulfate ion has the greater charge, we will need two atoms of NH4^+ that will sum up to give a charge 2+ which will balance the 2- coming from the sulfate polyatomic ion.

We will be having something like this:

NH4^+ + NH4^+ ----> 2NH4^ +

Now we have equal number of charges, two positive and two negative charges coming from two ammonium polyatomic ions and one sulfate polyatomic ion.

NH4^+ NH4^+ SO4^2-

This will make the formula for ammonium sulfate to be (NH4)2SO4

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what is the balanced equation for when an aqueous solution of hydrochloric acid reacts with sodium metal, aqueous sodium chlorin

FinnZ [79.3K]

Answer:

2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)

Explanation:

Na(s) + HCl(aq) —> NaCl(aq) + H2(g)

Writing an ionic equation will actually help us to understand the equation and also to balance it. This is illustrated below:

Na + H+Cl-

Na is higher than H in the activity series and as such, it will displaces H from the solution and form NaCl with H2 liberated as shown below

Na + H+Cl- —> Na+Cl- + H2

Now, put 2 in front of Na, H+Cl- and Na+Cl- to balance the equation as shown below:

2Na + 2H+Cl- —> 2Na+Cl- + H2

Now we can write the elemental equation as follow:

2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)

6 0

3 years ago

HELP!!! WILL GIVE BRAINLIEST!!!! 30 POINTS

NikAS [45]

Answer:

carbon = 7 atoms

hydrogen = 8 atoms

nitrogen = 4 atoms

oxygen = 2 atoms

Explanation:

Chemical formula = C₇H₈N₄O₂

Elements present:

carbon

hydrogen

nitrogen

oxygen

Number of atoms of each element.

carbon = 7 atoms

hydrogen = 8 atoms

nitrogen = 4 atoms

oxygen = 2 atoms

6 0

3 years ago

What of the following is made out of atoms? (HINT: vocabulary word "atom" or "matter") * 1 Air

MissTica

The correct answer would be air

8 0

3 years ago

A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di

Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

Initial mass MnO₂ = 0.6467g

Recovered mass = 0.3104g

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

Moles MnO₂ -Molar mass: 86.9368g/mol-:

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

Moles Cl⁻:

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

0.3439g of AlCl₃ are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0

2 years ago

Water is a produced when 30.0 grams of hydrogen reacts with 80.0 grams of oxygen what is the limiting reagent

irakobra [83]

The balanced equation for the reaction is as follows
2H₂ + O₂ --> 2H₂O
stoichiometry of H₂ to O₂ is 2:1
number of H₂ moles - 30.0 g / 2 g/mol = 15 mol
number of O₂ moles - 80.0 g / 32 g/mol = 2.5 mol
limiting reactant is the reagent in which only a fraction is used up in the reaction
if H₂ is the limiting reactant
if 2 mol of H₂ requires 1 mol of O₂
then 15 mol of H₂ requires 1/2 x 15.0 = 7.5 mol of O₂
but only 2.5 mol of O₂ is required
this means that O₂ is the limiting reagentt and H₂ is in excess

7 0

3 years ago