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sergey [27]
3 years ago
5

Which statement is true about the compound ammonium sulfate [(NH4)2SO4] ?

Chemistry
2 answers:
BabaBlast [244]3 years ago
4 0

Answer:

It is a salt of two polyatomic ammonium ions and one polyatomic sulfate ion

Explanation:

Ammonium Sulfate is an ionic compound formed by two polyatomic ions, Ammonium NH+4 and Sulfate SO−4 . ... Therefore, it will take two +1 ammonium ions to balance the one -2 sulfate ion. This will make the formula for Ammonium Sulfate (NH4)2SO4

timurjin [86]3 years ago
4 0

Answer:

A) It is a salt of two polyatomic ammonium ions and one polyatomic sulphate ion.

Explanation:

A polyatomic ion is an ion composed of two or more atoms. Polyatomic ions are covalently bonded groups of atoms with a positive or negative charge caused by the formation of an ionic bond with another ion. They behave as a single unit and are also known as molecular ion.

Ammonium sulphate [(NH4)2SO4] is an ionic compound formed by two polyatomic ions which are NH4^+ and SO4 ^2-

•In order for these two polyatomic ions to bond, the charges must be equal, opposite and give a net charge of zero.

•Since the sulfate ion has the greater charge, we will need two atoms of NH4^+ that will sum up to give a charge 2+ which will balance the 2- coming from the sulfate polyatomic ion.

We will be having something like this:

NH4^+ + NH4^+ ----> 2NH4^ +

Now we have equal number of charges, two positive and two negative charges coming from two ammonium polyatomic ions and one sulfate polyatomic ion.

NH4^+ NH4^+ SO4^2-

This will make the formula for ammonium sulfate to be (NH4)2SO4

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Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
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Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

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Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

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Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ

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