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Vanyuwa [196]
3 years ago
6

NEED HELP FRE BRAINLIST

Mathematics
2 answers:
snow_tiger [21]3 years ago
5 0
Phytagoras theorem
x^2 + 10^2 = 14^2
x^2 = 196-100 = 96
x = sqrt(96) = 9.80 ft
ans would be D) 9.8 ft
MAXImum [283]3 years ago
3 0

Answer:

D. 9.8 Valentines Day!

............

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Is #1 correct and I need help on #2 THANKS :)
horsena [70]
Answer 1 = I believe you are correct cause when doing area , remembering you times the different area of the sides


Answer 2 = I believe the answer is C (2,0009) cause remember adding when doing volume but there are few steps ..
. i have done the work for this and hoping my work helped the answer i got help you! comment below if you need anything , thanks , have a nice day!!
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3 years ago
What's 22 + 4? ghdjdhsbsjs
Debora [2.8K]

Answer:LOL 26

Step-by-step explanation: 22=4 IS LIKE EASY BUT IF YOU FORGOT THEN THATS FINE

4 0
4 years ago
At a convention for lawyers it was known that of the 100 present, at least one was honest, yet if you met any two of the lawyers
Temka [501]
From the given condition, there is only one honest lawyer present.
5 0
4 years ago
PLEASE HELP I NEED THIS TO BE DONE
yanalaym [24]
To find the mean you add all the #'s and divide by how many there are. 4+5+6+7 +8= 30 /5 is 6. Tara is right. 
5 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
2 years ago
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