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tatiyna
3 years ago
5

Which of the following will increase solubility the rate of the dissolving process of a gaseous solute in solvent? (mark all tha

t apply) please help!

Chemistry
1 answer:
Pepsi [2]3 years ago
7 0

Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

  • Increasing agitation
  • Increasing temperature
  • Increasing solute's partial pressure over the solvent
  • Increasing solute's surface area

Explanation:

When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.

Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.

As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.

When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.

Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

  • Increasing agitation
  • Increasing temperature
  • Increasing solute's partial pressure over the solvent
  • Increasing solute's surface area
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94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

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We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

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∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

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