The answer is 0.365:100.
v/c ratio represents ratio of speed of an electron (v) to the speed of light (c).
How is the speed of an electron calculated?
- The speed of an electron (v) is given by Bohr's model as-

Now, for the first excited state, n = 2.
e - Charge of electron =
×
C
h - Plank's constant =
×
ε₀- permittivity
×

- Put the above data in the formula-

- Now, the speed of light, c =
×
- Thus, the v/c ratio for an electron in the first excited state is calculated as-
= 
- Hence, the v/c ratio = 0.365:100.
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The periodic table arranges the elements into families and periods (vertical and horizontal rows). The elements in each family have similar properties. As you go across a row, the properties vary gradually from one element to the next. The table tells you what elements may have similar chemical and physical properties.The periodic table describes the atomic structure of all known elements. For instance, by looking at the periodic table, you can find out the atomic mass and the number of electrons the element has. Each element has its own separate set of such data. No two elements are the same.This is perhaps the most useful feature of the Periodic Table. It is an excellent reference tool. In one place, you can find many properties of an element.
The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels. Protons have a positive charge,neutrons have no charge, and electrons have a negative charge. A neutral atom contains equal numbers of protons and electrons.
Answer:

Explanation:
Hello there!
In this case, given the solubilization of cadmium (II) hydroxide:

The solubility product can be set up as follows:
![Ksp=[Cd^{2+}][OH^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BCd%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)
Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

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