Are bonds broken or formed, throughout each phase change present on a heating curve?
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In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
262mol 1=kg
g=1000
from stoichoimetry
x=102*1000/360
x=102000/360
x=283.33
density =m/v
=283.33/1.082
=262mol
g=1000
from stoichoimetry
x=102*1000/360
x=102000/360
x=283.33
density =m/v
=283.33/1.082
=262mol