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timofeeve [1]
3 years ago
10

Find the derivative of ln(cosx²).​

Mathematics
1 answer:
RoseWind [281]3 years ago
8 0

Answer:

\displaystyle \frac{dy}{dx} = -2x \tan (x^2)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = \ln (\cos x^2)

<u>Step 2: Differentiate</u>

  1. Logarithmic Differentiation [Derivative Rule - Chain Rule]:                       \displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}
  2. Trigonometric Differentiation [Derivative Rule - Chain Rule]:                   \displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}
  3. Basic Power Rule:                                                                                         \displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}
  4. Rewrite [Trigonometric Identities]:                                                              \displaystyle y' = -2x \tan (x^2)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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