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Ganezh [65]
2 years ago
10

Liam and his children went into a restaurant and where they sell drinks for $2 each and tacos for $3.50 each. Liam has $30 to sp

end and must buy at least 9 drinks and tacos altogether. If Liam decided to buy 5 tacos, determine the maximum number of drinks that he could buy. If there are no possible solutions, submit an empty answer.
Mathematics
2 answers:
nataly862011 [7]2 years ago
8 0

Answer:a

the number of drinks Liam can buy is 4 without going over his limit.

Step-by-step explanation:

scoray [572]2 years ago
3 0
Answer: the maximum number of drinks Liam can buy is 4 without over exceeding his price limit.

work:
$3.50 for 5 tacos is $17.50
9 - 5 tacos = 4 drinks
4 drinks x $2 = $8
$17.50 + $8 = $25.50 out of $30 price limit
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Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo
Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m

So the volume of the wall is:

V_w=0.1*12*4=4.8m^3

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Hence:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks

Solving for n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m

Entonces el volumen del muro es:

V_w=0.1*12*4=4.8m^3

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Por lo tanto:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos

Resolviendo para n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

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