The pleural cavity contains a little amount of liquid called as "pleural fluid".
<u>Explanation:</u>
The two thin serum producing membrane which gathers back itself resulted in membrane cavity of two layer pleural sac, which surrounds the lungs is termed as "pleura".
This cavity contain small amount of liquid named as pleural fluid, its function is to provide lubrication during respiration when the lungs expand and contract. Most fluid is generated via bulk flow through the parietal circulation and is reabsorbed by the lymphatic system.
Thus pleural fluid is continuously produced and reabsorbed. A few millilitres of pleural fluid is always present inside the intrapleural space in a typical 70 kg human.
Answer:
A
Explanation:
When you multiply a vector by a scalar the magnitude will change but the direction will not change.
Answer:
T_t = Ts (1-A
√ (Rs/D)
Explanation:
The black body radiation power is given by Stefan's law
P = σ A e T⁴
This power is distributed over a spherical surface, so the intensity of the radiation is
I = P / A
Let's apply these formulas to our case. Let's start by calculating the power emitted by the Sun, which has an emissivity of one (e = 1) black body
P_s = σ A_s 1 T_s⁴
This power is distributed in a given area, the intensity that reaches the earth is
I = P_s / A
A = 4π R²
The distance from the Sun Earth is R = D
I₁ = Ps / 4π D²
I₁ = σ (π R_s²) T_s⁴ / 4π D²
I₁ = σ T_s⁴ R_s² / 4D²
Now let's calculate the power emitted by the earth
P_t = σ A_t (e) T_t⁴
I₂ = P_t / A_t
I₂ = P_t / 4π R_t²2
I₂ = σ (π R_t²) T_t⁴ / 4π R_t²2
I₂ = σ T_t⁴ / 4
The thermal equilibrium occurs when the emission of the earth is equal to the absorbed energy, the radiation affects less the reflected one is equal to the emitted radiation
I₁ - A I₁ = I₂
I₁ (1 - A) = I₂
Let's replace
σ T_s⁴ R_s²/4D² (1-A) = σ T_t⁴ / 4
T_s⁴ R_s² /D² (1-A) = T_t⁴
T_t⁴ = T_s⁴ (1-A) (Rs / D) 2
T_t = Ts (1-A
√ (Rs/D)
Speed= f x λ ( f= frequency. λ = wavelength)
Speed = 2Hz x 6m
= 12m/s
It's implying that a constant force was applied throughout, which also means that there was a constant, negative acceleration. Because of that, the deceleration is equal to the change in velocity (-24.3 m/s) divided by the time (17.2 s):
![\frac{-24.3 m/s}{17.2 s}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-24.3%20m%2Fs%7D%7B17.2%20s%7D%20)
=-1.41279 m/s^2. The force is technically negative because it is causing a negative acceleration. Because F=ma: -2170kg m/sec^2=-(-1.41279 m/sec^2)m. m=
![\frac{-2170 kg m/s^2}{-1.41279 m/sec^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-2170%20kg%20m%2Fs%5E2%7D%7B-1.41279%20m%2Fsec%5E2%7D%20)
=<u>1535.9678 kg</u>