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Contact [7]
3 years ago
6

If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?

Physics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm

Magnification,

m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25

Hence, the magnification of the image is 0.25.

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