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3 years ago

Which of the following is the same as 727.526? In word form btw! ty

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer:

seven hundred twenty-seven and five hundred

twenty-six thousandths

Step-by-step explanation:

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you are assembling desserts with a friend together you can make 12 desserts in 5 minutes. how many can you make in 20 minutes?

Sever21 [200]

You can solve this in two ways.

First way:
Let’s find out how many my friend makes in one minute.
12/5=2.4
He makes 2.4 in one minute. Let’s multiply that by 20 to find what he makes in 20 minutes.
2.4•20=48
My friend made 48 desserts.

Second way:
Let’s make a ratio.
12 desserts:5 minutes
X desserts: 20 minutes
Whatever you do to one side, you have to do to the other. Since you are multiplying the minutes by 4, you have to multiply the desserts by 4.
12•4=48

So, my friend made 48 desserts.
Tell me if this helps!!!

3 0

3 years ago

What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0

3 years ago

X/2 - y/3 = 3/2<br>X/3 + y/2 = 16/3

Ivenika [448]

X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)

x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6

4 0

2 years ago

Please help!!!!!!!!!!

Ipatiy [6.2K]

You should get the app "photomath" that will help out alot!!!

8 0

3 years ago

Perimeter, Area And Volume

Maslowich

$\large\huge\green{\sf{Answer:-}}$

<h3>area of shaded figure= </h3>

<h2>area of whole rectangle</h2>

= lengthx breadth=15x30= 450 cm²

<h3>area of unshaded region= lengthx breadth= (30-8)x 15cm²= 22x 15cm²= 330cm²</h3>

<h3>are of shaded region</h3>

= area of whole rectangle -area of unshaded region= 450cm²-330cm²= 120cm²

therefore 120 is correct answer

6 0

2 years ago